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2 years ago

G(a) = 3a + 2 f(a)=2a-4 Find (g/f)(3)

Mathematics

1 answer:

Basile [38]2 years ago

7 0

Answer:(gf)(3)=g(3)f(3) g(a)=3a+2 or g(3)=3(3)+2=9+2 =11 f(a)=2a−4 f(3)=2(3)−4=6−4=2 g(3)f(3)=112. Answer

Step-by-step explanation:

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When the Bucks play Chiefs at football, the probability that the Chiefs, on present form, will win is 0.56. In a competition, th

Tom [10]

Answer:

The probability that Swallows will win the trophy is 0.8064

The probability that Rucks will win the trophy is 0.1936

Step-by-step explanation:

For each game, there are only two possible outcomes. Either the Swallows win, or they do not. The probability of them winning a game is independent of any other game, which means that the binomial probability distribution is used.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Probability the Swallows wins is 0.56

This means that $p = 0.56$

2 games:

This means that $n = 2$

The probability that Swallows will win the trophy is

Probability they win at least one game, so:

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{2,0}.(0.56)^{0}.(0.44)^{2} = 0.1936$

Then

$P(X \geq 1) = 1 - 0.1936 = 0.8064$

0.8064 = 80.64% probability the Swallows win the trophy and 0.1936 probability that the Rucks win the trophy.

5 0

3 years ago

When is written as a decimal, how many digits are in the smallest sequence of repeating digits?

dalvyx [7]

Answer:

1 number

Step-by-step explanation:

6.66

6.6 recurring

so the smallest sequence must be 6.6'

7 0

4 years ago

A flagpole is supported by a wire fastened 60 feet from its base. The wire is longer than the height it reaches on the flagpole.

maxonik [38]

Answer:

135.5ft

Step-by-step explanation:

THIS COMPLETE THE QUESTION

flagpole is supported by a wire fastened 60 feet from its base. The wire is 14 feet longer than the height it reaches on the flagpole. Find the length of the wire.

Let X be the length of the wire

Let y be the height of the pole

X= Y + 14

Y= X -14

We can form a right angle triangle form this, where X denote the Hypotenose, Y is the Opposite, and 60feet is the Adjacent.(CHECK THE ATTACHMENT FOR THE TRIANGLE)

Using Pythagoras theorem

X²= 60² + Y²

X² = 3600 + Y²

if we subsitute for Y we have

X² = 3600 + (X -14)²

X² = 3600 +X² -14X-14X+196

X²-X²+ 28X= 3600+196

28X= 3796

X= 3796/28

=135.5ft

hence length of the wire is 135.5ft

8 0

3 years ago

What is the GCF of 15r,25

xz_007 [3.2K]

The GCF of 15 and 25 would be 5

5 0

3 years ago

Read 2 more answers

This diagram shows triangles ABC and PQR. ABC is mapped to PQR by combining two single transformations. The first is a rotation

dedylja [7]

Answer:

enlarge by -2 by centre point (3,1)

Step-by-step explanation:

6 0

3 years ago