Answer:
The inverse of f(x) is 
(x) = ± 
+ 
Step-by-step explanation:
To find the inverse of the quadratic function f(x) = ax² + bx + c, you should put it in the vertex form f(x) = a(x - h)² + k, where
- h =
∵ f(x) = 3x² - 3x - 2
→ Compare it with the 1st form above to find a and b
∴ a = 3 and b = -3
→ Use the rule of h to find it
∵ h = 
= 
=
∴ h =
→ Substitute x by the value of h in f to find k
∵ k = 3( )² - 3( ) - 2
∴ k = 
→ Substitute the values of a, h, and k in the vertex form above
∵ f(x) = 3(x - )² +
∴ f(x) = 3(x - )² - 
Now let us find the inverse of f(x)
∵ f(x) = y
∴ y = 3(x - )² -
→ Switch x and y
∵ x = 3(y - )² -
→ Add to both sides
∴ x + = 3(y - )²
→ Divide both sides by 3
∵ 
= (y - )²
→ Take √ for both sides
∴ ± = y -
→ Add to both sides
∴ ± + = y
→ Replace y by (x)
∴ (x) = ± +
∴ The inverse of f(x) is (x) = ± +
Answer:
Step-by-step explanation:
true
Sin³ x-sin x=cos ² x
we know that:
sin²x + cos²x=1 ⇒cos²x=1-sin²x
Therefore:
sin³x-sin x=1-sin²x
sin³x+sin²x-sin x-1=0
sin³x=z
z³+z²-z-1=0
we divide by Ruffini method:
1 1 -1 -1
1 1 2 1 z=1
-------------------------------------
1 2 1 0
-1 -1 -1 z=-1
--------------------------------------
1 1 0 z=-1
Therefore; the solutions are z=-1 and z=1
The solutions are:
if z=-1, then
sin x=-1 ⇒x= arcsin -1=π+2kπ (180º+360ºK) K∈Z
if z=1, then
sin x=1 ⇒ x=arcsin 1=π/2 + 2kπ (90º+360ºK) k∈Z
π/2 + 2kπ U π+2Kπ=π/2+kπ k∈Z ≈(90º+180ºK)
Answer: π/2 + Kπ or 90º+180ºK K∈Z
Z=...-3,-2,-1,0,1,2,3,4....
-3x-3 = 4x-3
-3 = 7x-3
0 = 7x
x = 0
We need a least common denominator
19 1/8 and 2 1/4 (also = to 2 2/8)
19 1/8-2 2/8= 16 7/8
16 7/8 divided by 5
ANSWER: 3 3/8 in
