First, an introduction: If the equation of the circle were x^2 + y^2 = 144, then the center would be at (0,0) and the radius would be 12. Note that the distance from the center to P(10,10) is 10sqrt(2), or 14.14. Thus, in this example, P would be OUTSIDE the circle (since 14.14 is greater than the radius 12).
Now let's focus on <span>(x-1)^2 + (y-2)^2 =144. Let x = 12 as an example; find the corresponding y: 9^2 + (y-2)^2 = 144, or (y-2)^2 = 63, and so y-2 is approx. -8 or +8. Then y (for x = 12) is either approx. -10 or 6: (12,-10) or (12,6). Are these inside the circle or outside?
A better way to address this would be as follows:
Find the distance from the center (1, 2) to the point P(10,10). If this distance is less than 12, the point P is inside C; if greater than 12, P is outside C.
This distance is sqrt( (10-2)^2 + (10-1)^2 ), or sqrt (64+81) = sqrt(145).
This is LARGER than sqrt(144). Thus, P is OUTSIDE the circle C.</span>
It is A. Because the point a would be on the -1 and the b would be on the -7 and the c would be on the -4
7.00
97.974436/14 = 6.998174
So if we round our answer to two decimal places it should equal 7.00
<span>Let n, n+2, and n+4 represent the three consecutive even integers. Or 2 in your case </span>
Answer:
6 +7x
Step-by-step explanation:
To write an English expression as an algebraic one, you must first understand what the English is telling you. Then the translation is straightforward.
<h3>Algebraic representation</h3>
A plus sign (+) signifies addition. Multiplication is signified several different ways. The simplest is writing the factors next to each other.
<h3>Parsing the English</h3>
The objects involved in the addition are 6 and a product:
6 + product
The product is said to consist of two factors: 7 and "a number". The instructions say to use "x" for "a number", so the product can be written ...
7x
<h3>Algebraic expression</h3>
Then the complete algebraic expression is ...
6 +7x
