Question

What are the zeros of the polynomial function f(x) = x3 + x2 − 42x?

Answer 1

Answer:

D. -7, 0, 6

Step-by-step explanation:

$x^3+x^2-42x=0$

$x(x^2+x-42)=0$

$x(x^2-6x+7x-42)=0$

$x(x-6)(x+7)=0$

ZEROS:

x = 0

x = 6

x = -7

Hope this helps!