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AlexFokin [52]
3 years ago
7

HELPPPPPPPPPP HELPPPPPP

Mathematics
2 answers:
kifflom [539]3 years ago
4 0

Answer:

14c decrease Option D

Step-by-step explanation:

The temperature was 8c at 12 am and -7c at 7 pm to find the difference subtract to get 14c.

snow_tiger [21]3 years ago
4 0

whats wrong im only in 7th grade

Step-by-step explanation:

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Which of the following numbers are composite 47 or 12 or 16 or 43 which number is it
solniwko [45]

Answer:

1=1

Step-by-step explanation:

yes

5 0
3 years ago
What words do I fill the blanks in with? Please hurry <3
xeze [42]

Answer:

It says why you suck at cooking

Hope this helps!! :D

7 0
2 years ago
Z is proportional to x^3. describe exactly what will happen to x when z became 8 times greater
Reil [10]

Answer: x is doubled.

Step-by-step explanation:

A proportional relationship between x and y is written as:

y = k*x

where k is called the constant of proportionality.

In this case, we know that we have a proportional relationship between z and x^3

Then:

z = k*x^3

What will happen to x when z is 8 times greater?

Let's rewrite this equation for two new quantities, z' and x'

z' = k*(x')^3

Now we need to replace z' by 8*z, then:

8*z =  k*(x')^3

We want to find a relationship between x' and x.

And by the first relationship, we know that:

z =  k*x^3

Then we can replace this in the equation "8*z =  k*(x')^3" to get:

8*(k*x^3) =  k*(x')^3

8*k*x^3 = k*(x')^3

Now we can divide both sides by k, so we get:

8*x^3 = (x')^3

Now we can apply the cubic root to both sides, to get:

∛(8*x^3) = ∛(x')^3

∛(8)*x = x'

2*x = x'

Then when we increase the value of z 8 times, the value of x will be doubled.

8 0
2 years ago
A pipe that is 120 cm long resonates to produce sound of wavelengths 480 cm, 160 cm, and 96 cm but does not resonate at any wave
erma4kov [3.2K]

Answer:

A Pipe that is 120 cm long resonates to produce sound of wavelengths 480 cm, 160 cm and 96 cm but does not resonate at any wavelengths longer than these. This pipe is:

A. closed at both ends

B. open at one end and closed at one end

C. open at both ends.

D. we cannot tell because we do not know the frequency of the sound.

The right choice is:

B. open at one end and closed at one end .

Step-by-step explanation:

Given:

Length of the pipe, L = 120 cm

Its wavelength \lambda_1 = 480 cm

                         \lambda_2 = 160 cm and \lambda_3 = 96 cm

We have to find whether the pipe is open,closed or open-closed or none.

Note:

  • The fundamental wavelength of a pipe which is open at both ends is 2L.
  • The fundamental wavelength of a pipe which is closed at one end and open at another end is 4L.

So,

The fundamental wavelength:

⇒ 4L=4(120)=480\ cm

It seems that the pipe is open at one end and closed at one end.

Now lets check with the subsequent wavelengths.

For one side open and one side closed pipe:

An odd-integer number of quarter wavelength have to fit into the tube of length L.

⇒  \lambda_2=\frac{4L}{3}                                   ⇒  \lambda_3=\frac{4L}{5}

⇒ \lambda_2=\frac{4(120)}{3}                              ⇒  \lambda_3=\frac{4(120)}{5}

⇒ \lambda_2=\frac{480}{3}                                  ⇒  \lambda_3=\frac{480}{5}

⇒ \lambda_2=160\ cm                           ⇒   \lambda_3=96\ cm  

So the pipe is open at one end and closed at one end .

6 0
3 years ago
Need help with this as soon as possible.
jok3333 [9.3K]

-4x^2-28x-68

hope this helped!

3 0
3 years ago
Read 2 more answers
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