All categories

3 years ago

Please please need help on this been trying

Mathematics

1 answer:

mariarad [96]3 years ago

7 0

Answer:

y = -7x + 0

Step-by-step explanation:

slope-intercept form is y = mx + b where m is the slope and b is the y-intercept

use any of the points on the graph. (0,0) (-1,7). find the slope

slope = y2 - y1/ x2 - x1

slope 7 - 0/ -1-0 = 7/-1 = -7. our slope is -7

so now we already have y = -7x + b. but we still have to find the y-intercept.

-7/1 = y - 7/x - (-1) cross multiply.

y - 7 = -7x - 7

y + 7x = -7 + 7

y + 7x = 0

y = -7x + 0

You might be interested in

I NEED HELP PLEASE, THANKS! :)

KIM [24]

Answer: tan(14x)

<u>Step-by-step explanation:</u>

Consider the Sum Formula for tan:

$tan(A + B)=\dfrac{tan(A)+tan(B)}{1-tan(A)(tan(B)}\\\\\\tan(9x+5x)=\dfrac{tan(9x)+tan(5x)}{1-tan(9x)(tan(5x)}\\\\\\\large\boxed{tan(14x)}=\dfrac{tan(9x)+tan(5x)}{1-tan(9x)(tan(5x)}$

3 0

3 years ago

Read 2 more answers

3/4 + 7/8 =??????????????????

Vsevolod [243]

Answer:

13/8

in decimal form it is 1.625

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Which of the following matrices is the solution matrix for the given system of equations? x + 5y = 11 x - y = 5

givi [52]

<h2>The required solution is x = 6 and y = 11 </h2>

Step-by-step explanation:

Given system of equations are

x+5y = 11 and x-y =5

$A= \left[\begin{array}{cc}1&5\\1&-1\end{array}\right]$ $X=\left[\begin{array}{c}x\\y\end{array}\right]$

and $B= \left[\begin{array}{c}11\\5\end{array}\right]$

∴AX=B

$adj A = \left[\begin{array}{cc}{-1}&{-5}\\{-1}&1\end{array}\right]$

$A= \left|\begin{array}{cc}1&5\\1&-1\end{array}\right|=-6$

∴ $A^{-1} =\frac{adj A}{|A|}$

So, $A^{-1} =\frac{ \left[\begin{array}{cc}{-1}&{-5}\\{-1}&1\end{array}\right]}{-6}$

$A^{-1} ={ \left[\begin{array}{c \c} {{\frac{1}{6} }}&{\frac{5}{6}}\ \\ {{\frac{1}{6} }}&{\frac{-1}{6}} \end{array}\right]}$

$X =A^{-1}\times B$

⇒ $\left[\begin{array}{c}x\\y\end{array}\right] ={ \left[\begin{array}{c \c} {{\frac{1}{6} }}&{\frac{5}{6}}\ \\ {{\frac{1}{6} }}&{\frac{-1}{6}} \end{array}\right]} \times \left[\begin{array}{c}11\\5\end{array}\right]$

⇒ $\left[\begin{array}{c}x\\y\end{array}\right] ={ \left[\begin{array}{c} {6}\\ {11} \end{array}\right]}$

∴ x= 6 and y = 11

The required solution is x = 6 and y = 11

7 0

3 years ago

Solve for x in the equation 2x2-5x+1 -3.<br> 29<br> 41<br> o xtv<br> O<br> O<br> o x + V47

Shkiper50 [21]

Answer: B.

Step-by-step explanation: 2x² + x - 6x - 3

= 2x² - 5x - 3

Tell me if you get the answer right.

8 0

2 years ago

Can someone help please I’ll give brainliest!

Alla [95]

Answer: F.

Step-by-step explanation:

First we have to determine the common factor for all of them, which in this case is 11.75. Then we have to multiply that by 40 which gives us 470.

7 0

3 years ago