First, let's find the x and y intercepts
In the first equation
y - 4x = -1
Put x =0
y= - 1
(0, -1)
Put y=0 and the n solve for x
0 - 4x = -1
-4x = -1
x=0.25
(0.25 , 0)
The points for the first equation is (0, -1 ) and (0.25, 0)
Next is to find the intercts for the second equation
y + x = 4
put x=0
y = 4
(0, 4)
Put y =0
0 + x = 4
x = 4
( 4, 0)
The points for the second equation are;
(0, 4) and (4, 0)
Below is the graph
Answer:
The average value of over the interval
is
.
Step-by-step explanation:
Let suppose that function is continuous and integrable in the given intervals, by integral definition of average we have that:
(1)
(2)
By Fundamental Theorems of Calculus we expand both expressions:
(1b)
(2b)
We obtain the average value of over the interval
by algebraic handling:
The average value of over the interval
is
.