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yKpoI14uk [10]
3 years ago
11

Which one of the following measurements represents the longest distance

Mathematics
1 answer:
strojnjashka [21]3 years ago
5 0
It Would be A 1km because its 1000 meters
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write the point slope form of the equation for a line that passes through the point 3, 1 and is parallel to the line y=3x+3
Galina-37 [17]

Answer:

y=3x-8

Step-by-step explanation:

If the line is parallel to y=3x+3, that would mean that they would have the same slope of 3. Then, once you plug it back into the equation along with the point given, you would get 1=3(3)+b. Solve from there, and you get b= -8. In conclusion, your point slope formula comes out to be y=3x-8.

Hope this helps! :)

4 0
3 years ago
Find f(-1) if f(x) = -2x^2 -x
kykrilka [37]

I hope it was helpful to you

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3 0
3 years ago
Find the perimeter of the shaded region. Round your answer to the nearest hundredth. Help me por favor
timurjin [86]

Answer:

19.15

Step-by-step explanation:

so find the circumference of the circle using c=2*pi*r it's like 18.849. then find the perimeter of the box so p=2l+2w and it's like 38. so subtract the circle circumference from 38 so 38-18.849=19.15

6 0
3 years ago
the pressure exerted on the floor by the heel of someone's shoe is inversely proportional to the square of the width of the heel
Katen [24]
P = k/w^2 

<span>first of all you need to find k </span>
<span>But I kind of don't like the units of each value so let say </span>
<span>400KPa = 4 * 10^5 Pa = 4 * 10^5 N/m^2 </span>
<span>2 cm = 2 * 10^-2 m </span>

<span>input values in the equation </span>

<span>4*10^5 = k/(4*10^-4) >>> k = 160 N </span>

<span>P = 160/w^2 </span>
<span>it said if she wears a heel with a width of .5 cm </span>

<span>P = 160(0.5 * 10^-2)^2 >>> P = 6400 KPa</span>
4 0
3 years ago
For what values of t on the interval [0, 21 ]is the instantaneous velocity positive​ (the projectile moves​ upward)?
OLEGan [10]

Answer:

0 <=t<=21

Step-by-step explanation:

Projectile is Moving upwards on an interval of (0 to 21), if we plot Velocity vs Time and denote positive y-axis above 0 and negative y-axis below  0(for velocity), then from 0 to 21 t projectile is moving upwards and has positive velocity, when the projectile reaches the top of it's motion and returns back down to ground it's velocity is negative and is plotted below the y =0 (note that is for t > 21).

hence for the interval 0 <=t <=21 the instantaneous velocity is positive (Note, instantaneous velocity is also the derivative of the velocity or the slope ).

8 0
3 years ago
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