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2 years ago

7

Hello, i am having a hard time solving this. If anyone can please explain how to solve it in order for me to solve future questi

ons of the same type?
f(x) = 5x3 – 2x and g(x) = 3x3

perform the following :

f(g(x))

g(f(x))

----- Thank you for your help

1 answer:

lora16 [44]2 years ago

7 0

Answer:

Step-by-step explanation:

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One number is five less than a second number. Five times the first is 15 more than 6 times the second. Find the numbers

Shalnov [3]

Answer:

x = -45, y = -40

Step-by-step explanation:

Based on the first clue, we find out that

x + 5 = y

5x = 6y + 15

We can re-write the first equation to x = y - 5.

Therefore, the second equation can also be written as 5(y - 5) = 6y + 15

This can be simplified to 5y - 25 = 6y + 15

We can subtract 6y from each side, and add 25 to each side;

5y - 6y = 15 + 25

Therefore, -y = 40

Therefore y = -40.

Now let's plug this back into the original equation, to get : x + 5 = -40

x=-45

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2 years ago

If z varies inversely as w, and z= 3 when w=4, find z when w=2.<br> Z=

vivado [14]

Answer:

6

Step-by-step explanation:

Inverse proportion.

z = k/w

z = 3, w = 4

Solve for k constant.

3 = k/4

(4)3 = (4)k/4

12=k

The value of k constant is 12.

z = k/w

Put w as 2 and k as 12 and solve for z.

z = 12/2

z = 6

The value of z when w equals 2 is 6.

8 0

3 years ago

What is the value of a?

Annette [7]

Answer:

<h2>a = 16</h2>

Step-by-step explanation:

Look at the picture.

The formula of an area of a trapezoid is:

$A=\dfrac{b_1+b_2}{2}\cdot h$

$b_1,\ b_2$ - bases

$h$ - height

We have:

$A=128,\ b_1=a+2,\ b_2=a-2,\ h=8$

Substitute:

$128=\dfrac{a+2+a-2}{2}\cdot8\\\\128=\dfrac{2a}{2}\cdot8$

$128=8a$ <em>divide both sides by 8</em>

$16=a\to a=16$

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3 years ago

Estimate the product of 67 an 73 round each number to the neares tenes

vampirchik [111]

Answer:

4900

Step-by-step explanation:

73*67

70*70

7*7(10^2)

49(100)

4900

6 0

3 years ago

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What is the solution to the inequality

Dvinal [7]

Answer:

p > 5 and p <-8

Step-by-step explanation:

To solve this, you first need to isolate p.

First add 6 on both sides of the equation:

$-6 + |2p+3| >7\\\\(+6) -6 + |2p+3| >7 +6\\\\2p + 3 > 13$

Then subtract 3 from both sides of the equation.

$2p+3-3>13-3\\\\2p > 10\\$

The divide both sides by 2.

$\dfrac{2p}{2}>\dfrac{10}{2}\\\\p>5$

Another solution is possible because of the absolute value.

If $|2p+3|>13$

Then $|2p+3|$

<em>Thus we can solve the second solution:</em>

$|2p+3|$

$2p+3$

Isolate P again by subtracting both sides by 3

$2p+3-3$

$2p$

Then divide both sides by 2:

$\dfrac{2p}{2}$

$p$

3 0

3 years ago

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