A, B and C working together will finish same piece of work in 10 days
A can do a piece of work in 20 days. That is A is doing the work at a rate of 1 / 20. Therefore
B = 1 / 30
C = 1 / 60
A, B and C working togehter their rate will be added together =
A + B + C = 1 / 20 + 1 / 30 + 1 / 60 = 1 / 10
so they can work together to finish same piece of work in 10 days
Answer:
Constraint 2: 3X1 + 3X2 ≤ 480
Step-by-step explanation:
Less than/equal to 300, would satisfy this one
Answer:the answer c
Step-by-step explanation:
Answer: 9 subtracted from y and multiplied by 2
Answer:
= 20 - 9n
Step-by-step explanation:
There is a common difference d between consecutive terms, that is
d = 2 - 11 = - 7 - 2 = - 9
This indicates the sequence is arithmetic with nth term
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Here a₁ = 11 and d = - 9 , then
= 11 - 9(n - 1) = 11 - 9n + 9 = 20 - 9n
