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Alexxx [7]
2 years ago
10

Which fraction would you find marked on a ruler?

Mathematics
1 answer:
olga_2 [115]2 years ago
7 0

Answer:

1/8

Step-by-step explanation:

Generally, rulers, yardsticks and tape measures are marked in 16ths 8ths and quarter inches

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19. Charlotte has a success rate of about 20%
aksik [14]

Answer:

P(x \ge 5) = 0.60

Step-by-step explanation:

Given

S = \{5, 2, 7, 2, 3, 4, 10, 6,4,6,3, 6, 6, 4, 8,5,7,7,1,5\}

n(S) = 20

Required

P(x \ge 5)

First, we count the number of trials that are at least 5

x = \{5, 7,  10, 6,6, 6, 6, 8,5,7,7,5\}

So, we have:

n(x \ge 5) = 12

So, we have:

P(x \ge 5) = \frac{n(x \ge 5)}{n(S)}

This gives

P(x \ge 5) = \frac{12}{20}

P(x \ge 5) = 0.60

4 0
2 years ago
Given the two perallel line ,determine the measure of x a= x=125 b= x=135 c= x=45 d= x=55
dedylja [7]

Answer:a

Step-by-step explanation:

7 0
3 years ago
May you please help me
Dmitry_Shevchenko [17]
Hey where is the graph for Function B?
4 0
2 years ago
Read 2 more answers
A system of equations is shown below. y = –x – 3 5x + 2y = 9 What is the solution to this system?
erastovalidia [21]

Answer:

x=5\ and\ y=-8

The solution of the system can be given as (5,-8).

Step-by-step explanation:

Given system of equations:

y=-x-3

5x+2y=9

To solve the given system of equations:

Solution:

We will use substitution to solve the given system.

We will substitute the y values in terms of x from the equation y=-x-3 into the other equation to solve for x

Substituting y=-x-3 into 5x+2y=9.

We have:

5x+2(-x-3)=9

<em>Using distribution.</em>

5x-2x-6=9

<em>Combining like terms.</em>

3x-6=9

Adding 6 both sides.

3x-6+6=9+6

3x=15

Dividing both sides by 3.

\frac{3x}{3}=\frac{15}{3}

∴ x=5

<em>Plugging in x=5 into y=-x-3.</em>

We have,

y=-5-3

∴ y=-8

The solution of the system can be given as (5,-8).

4 0
3 years ago
Answer Are SSS,ASA,AAS,SAS Not enough Information <br> PLEASE HELP ME PLEASE
Leokris [45]

Answer:

1.SAS

2. AAS

3.SAS

4.SSS

5.SSS

6.SSS

Step-by-step explanation:

3 0
3 years ago
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