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Arlecino [84]
3 years ago
10

What is the constant variation k of the direct variation y=kx through (-3,2)

Mathematics
1 answer:
Alinara [238K]3 years ago
6 0
What is the constant variation k of the direct variation
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What is (10y+6) (8y-6) ?
ANEK [815]

Answer:

y = 3/4 or y = -3/5

Step-by-step explanation:

Solve for y:

(8 y - 6) (10 y + 6) = 0

Hint: | Find the roots of each term in the product separately.

Split into two equations:

8 y - 6 = 0 or 10 y + 6 = 0

Hint: | Look at the first equation: Factor the left hand side.

Factor constant terms from the left hand side:

2 (4 y - 3) = 0 or 10 y + 6 = 0

Hint: | Divide both sides by a constant to simplify the equation.

Divide both sides by 2:

4 y - 3 = 0 or 10 y + 6 = 0

Hint: | Isolate terms with y to the left hand side.

Add 3 to both sides:

4 y = 3 or 10 y + 6 = 0

Hint: | Solve for y.

Divide both sides by 4:

y = 3/4 or 10 y + 6 = 0

Hint: | Look at the second equation: Factor the left hand side.

Factor constant terms from the left hand side:

y = 3/4 or 2 (5 y + 3) = 0

Hint: | Divide both sides by a constant to simplify the equation.

Divide both sides by 2:

y = 3/4 or 5 y + 3 = 0

Hint: | Isolate terms with y to the left hand side.

Subtract 3 from both sides:

y = 3/4 or 5 y = -3

Hint: | Solve for y.

Divide both sides by 5:

Answer: y = 3/4 or y = -3/5

4 0
3 years ago
Seven less than one half of x
damaskus [11]

Answer:

X/2-7

Step-by-step explanation:

any number which is said to be less than another number let's say b should be subtracted from b.

7 0
3 years ago
PLEASE help me ; - ; (USAtest prep)
nadezda [96]
What do u want help with and take it easy btw
4 0
2 years ago
The cost T, in dollars, of tuition and fees at Addison Technical College is $125 per credit plus an $85 registration fee. How ma
Sladkaya [172]

Answer:

13

Step-by-step explanation:

1710/125 = 13.68

You need

125 x 13 = 1710

A student could take 13 credits.

8 0
3 years ago
If f(x)=log2(x+4), what is f^-1(3)?
zalisa [80]
f\left( x \right) =\log _{ 2 }{ \left( x+4 \right)  } \\ \\ \log _{ 2 }{ \left( x+4 \right)  } =y\\ \\ { 2 }^{ y }=x+4

\\ \\ x={ 2 }^{ y }-4\\ \\ \therefore \quad { f }^{ -1 }\left( x \right) ={ 2 }^{ x }-4\\ \\ \therefore \quad { f }^{ -1 }\left( 3 \right) ={ 2 }^{ 3 }-4=4
3 0
3 years ago
Read 2 more answers
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