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1 year ago

The height of a triangle is 4 feet less than the length of its base, b. The area of the triangle is 30 square feet.

Mathematics

1 answer:

Papessa [141]1 year ago

8 0

Answer:

base(b)=10 and height(h)=6

Step-by-step explanation:

From the question,

base(b)=x feet

height(h)=(x-4) feet

Area(A)=30 square feet

Now,

We know,

Area of triangle(A)=1/2*b*h

or, 30=1/2*x*(x - 4)

or, 30=1/2*x^2 -4x

or, 30*2=x^2 -4x

or, 60=x^2 -4x

or, 0 = x^2 -4x -60

or, 0 = x^2 +6x - 10x -60

or, 0 = x(x + 6) -10(x + 6)

or, 0 = (x+6) (x-10)

Either,

x+6=0. or, x-10=0

or,x= -6. or, x= 10

Since, the base of the triangle can not be negative number then, x≠ -6feet but x=10feet

Lastly,

Height(h)=X - 4

=10 - 4

=6 feet

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The decimal equivalent of the fraction of months with 31 days is 0.583

Given:

$Total = 12$ --- months in a year

$Months = 7$ --- months with 31 days

The fraction (n) of months with 31 days is:

$n = \frac{Months}{Total}$

So, we have:

$n = \frac{7}{12}$

The decimal equivalent is:

$n = 0.583$

Hence, (c) is correct.

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2 years ago

Which is true?

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The Statement 
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2 years ago

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Select all the conditions for which it is possible to construct a triangle. (7.G.1.2) Group of answer choices a. A triangle with

saw5 [17]

Answer:

b, d, e, f

Step-by-step explanation:

Here are the applicable restrictions:

The sum of angles in a triangle is 180°, no more, no less.
The sum of the lengths of the two shortest sides exceeds the longest side.
When two sides and the angle opposite the shortest is given, the sine of the given angle must be at most the ratio of the shortest to longest sides.

a. A triangle with angle measures 60°, 80°, and 80° (angle sum ≠ 180°, not OK)

b. A triangle with side lengths 4 cm, 5 cm, and 6 cm (4+5 > 6, OK)

c. A triangle with side lengths 4 cm, 5 cm, and 15 cm (4+5 < 15, not OK)

d. A triangle with side lengths 4 cm, 5 cm, and a 50° angle across from the 4 cm side (sin(50°) ≈ 0.766 < 4/5, OK)

e. A triangle with angle measures 30° and 60°, and an included 3 cm side length (OK)

f. A triangle with angle measures 60°, 20°, and 100° (angle sum = 180°, OK)

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Additional comment

In choice "e", two angles and the side between them are specified. As long as the sum of the two angles is less than 180°, a triangle can be formed. The length of the side is immaterial with respect to whether a triangle can be made.

The congruence postulates for triangles are ...

SSS, SAS, ASA, AAS, and HL

These essentially tell you the side and angle specifications necessary to define a singular triangle. As we discussed above, the triangle inequality puts limits on the side lengths specified in SSS. The angle sum theorem puts limits on the angles when only two are specified (ASA, AAS).

In terms of sides and angles, the HL postulate is equivalent to an SSA theorem, where the angle is 90°. In that case, the angle is opposite the longest side (H). In general, SSA will specify a singular triangle when the angle is opposite the longest specified side, regardless of that angle's measure. However, when the angle is opposite the shortest specified side, the above-described ratio restriction holds. If the sine of the angle is less than the ratio of sides, then two possible triangles are specified.

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1 year ago

f the price charged for a candy bar is p(x) cents, where p (x )equals 162 minus StartFraction x Over 10 EndFraction , then x t

andreev551 [17]

Answer:

a. 1620-x^2

b. x=810

c. Maximum value revenue=$656,100

Step-by-step explanation:

(a) Total revenue from sale of x thousand candy bars

P(x)=162 - x/10

Price of a candy bar=p(x)/100 in dollars

1000 candy bars will be sold for

=1000×p(x)/100

=10*p(x)

x thousand candy bars will be

Revenue=price × quantity

=10p(x)*x

=10(162-x/10) * x

=10( 1620-x/10) * x

=1620-x * x

=1620x-x^2

R(x)=1620x-x^2

(b) Value of x that leads to maximum revenue

R(x)=1620x-x^2

R'(x)=1620-2x

If R'(x)=0

Then,

1620-2x=0

1620=2x

Divide both sides by 2

810=x

x=810

R(x)=1620x-x^2

R(810)=1620x-x^2

=1620(810)-810^2

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