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3 years ago

How do I put 6.50s+2.00d=836.50 into a calculator?

Mathematics

1 answer:

Virty [35]3 years ago

4 0

Answer:

isolate one of the variables so that the opposite side can be put in

d=(6.50s-836.50)/2

Step-by-step explanation:

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Mari spends $6 on cheese for a party she also plans to buy b boxes of crackers that cost $3 per box

PSYCHO15rus [73]

Answer:

The answer is 6+3b<or equal to 15

Step-by-step explanation:

3 0

3 years ago

A mother is now nine times as old as her son. In four years' time she will be five times as old as her son.What are their presen

ivanzaharov [21]

Answer:

son = 4

mom=36

m = 9s

m + 4 = 5(s+4)

m + 4 = 5s + 20

9s + 4 = 5s + 20

4s = 16

s = 4

m = 36

Step-by-step explanation:

5 0

3 years ago

-5(a + 3) = -55 What is the value of a?

Kobotan [32]

Answer:

a=8

Step-by-step explanation:

-5(a+3)=-55

First you times the bracket by -5

-5a-15=-55

Then you add the 15 to -55 because since the 15 is a negative on the right it has to be the opposite to the left

-5a=-40

Then you divide both sides by negative 5

-5a . = . -40

--------- ----------

- 5 -5

a= 8

5 0

4 years ago

(1 point) Consider the function f(x)=2x3−9x2−60x+1 on the interval [−4,9]. Find the average or mean slope of the function on thi

OlgaM077 [116]

Answer: c = 4.97 and c = -1.97

Step-by-step explanation: Mean Value Theorem states if a function f(x) is continuous on interval [a,b] and differentiable on (a,b), there is at least one value c in the interval (a<c<b) such that:

$f'(c) = \frac{f(b)-f(a)}{b-a}$

So, for the function f(x) = $2x^{3}-9x^{2}-60x+1$ on interval [-4,9]

$f'(x) = 6x^{2}-18x-60$

f(-4) = $2.(-4)^{3}-9.(-4)^{2}-60.(-4)+1$

f(-4) = 113

f(9) = $2.(9)^{3}-9.(9)^{2}-60.(9)+1$

f(9) = 100

Calculating average:

$6c^{2}-18c-60 = \frac{100-113}{9-(-4)}$

$6c^{2}-18c-60 = -1$

$6c^{2}-18c-59 = 0$

Resolving through Bhaskara:

c = $\frac{18+\sqrt{1740} }{12}$

c = $\frac{18+41.71 }{12}$ = 4.97

c = $\frac{18-41.71 }{12}$ = -1.97

Both values of c exist inside the interval [-4,9], so both values are mean slope: c = 4.97 and c = -1.97

7 0

3 years ago

Need help y+3=6(x+2)-3

olga_2 [115]

Slope-Intercept:

y + 3 = 6(x + 2) - 3

y + 3 = 6x + 12 - 3

-3 -3

y = 6x + 12

Standard:

y = 6x + 12

-6x -6x

-6x + y = 12

-1(-6x + y = 12)

6x - y = -12

Graph:

y = 6x + 12

↓ ↓

↓ y-intercept

slope

Start by graphing the y-intercept: (0, 12)

Then count the rise (up 6) and the run (right 1) from the y-intercept: (1, 18)

count the rise (down 6) and the run (left 1) from the y-intercept: (-1, 6)

4 0

3 years ago