I’m pretty sure males are ZZ. Let me know if I’m right and have a good rest of your day!
The survival of the 2 percent of the population is due to the presence of a gene obtained from other species. This gene must be responsible for developing resistance in the insects, against the insecticide that was used by the farmer. The gene got incorporated in only 2% of the insects and therefore, they survived and rest of them were susceptible to the insecticide and thus, died.
Answer:
Please, see the answer below.
Explanation:
The statement is inaccurate because a growing baby is not just a ball of multiplying cells that eventually grows large enough to form a baby.
<u>After fertilization and the formation of a single-cell zygote, the zygote continues to divide to form a ball of cells. However, at some points, the cells start to differentiate to give rise to various organs that make up the baby.</u>
<em>Without differentiation, there is not way the dividing cells will give rise to baby. Hence, a growing baby should be rather viewed as a ball of multiplying cells that eventually differentiates to form a baby.</em>
The answer is D) 1/2.
Let's imagine that two genes of the genotype can be analysed separately.
Black fur is determined by dominant allele B. In this case, parents Bb and BB will give offspring with only brown fur:
Parents: Bb x BB
Offspring: BB BB Bb Bb
Both homozygous (BB) and heterozygous (Bb) offspring will have black fur.
On the other hand, long tails are determined by recessive allele t. Parents Tt and tt will have 50% offspring with short tail and 50% offspring with long tail:
Parents: Tt x tt
Offspring: Tt Tt tt tt
Heterozygous offspring (Tt) will have short tail, and homozygous offspring (tt) will have a long tail.
So, the offspring will definitely have black fur and will not affect the fraction of the offspring with black fur and long tails from the cross of <span>BbTt × BBtt. But, </span>there will be 2 out of 4 offspring with short tails which is 50% or 1/2.
