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MatroZZZ [7]
1 year ago
11

A surfer paddles out past breaking waves, rides a wave, paddles back out past the breaking waves, rides another wave back to the

beach. Draw a sketch of a graph (with labels) that shows the surfer's possible distance from the beach over time. Show work
Mathematics
1 answer:
Karolina [17]1 year ago
8 0

Answer:

Past the waves to the beach

Step-by-step explanation:

They never went past the breaking waves that much and started at the beach

You might be interested in
A tortoise makes a journey in two parts; it can either walk at 4cm/s or crawl at 3cm/s. If the tottoise walks the first part and
Ugo [173]

Answer:

120

240

Step-by-step explanation:

We call the length of first part x

Length of second part = y

In the first scenario, it took the tortoise 110 sec to walk the first part and crawl the second.

So,

We have this equation,

x/4 + y/3 = 110

We take the LCM

(3x + 4y)/12 = 110

When we cross multiply

3x + 4y = 110x12

3x + 4y = 1320 ----- equation 1

For scenario 2

x/3 + y/4 = 100

When we take the LCM

(4x + 3y)/12 = 100

We cross multiply

4x + 3y = 100x12

4x + 3y = 1200 ------ equation 2

We now have two equations and we will solve for x and y using simultaneous linear equation.

3x + 4y = 1320 ----- 1

4x + 3y = 1200 ----- 2

We subtract equation 2 from 1 to get

- x + y = 120

We make y subject

y = x + 120 ----- 3

We put the value of y in equation 3 into equation 1

3x + 4(x + 120) = 1320

3x + 4x + 480 = 1320

7x + 480 = 1320

7x = 1320-480

7x = 840

We divide through by 7

x = 840/7

x = 120

We put value of x in equation 3

y = x + 120

y = 120 + 120

y = 240

120 and 240 are the lengths of the 2 parts of the journey.

Thanks

5 0
3 years ago
How many feet are in 2000 meters?
11Alexandr11 [23.1K]
First, note that 1 meter is equal to 3.28084 feet.

Next, multiply 
2000 m • 3.28084 = 6561.68 ft
6 0
3 years ago
Read 2 more answers
What is greatest common factor of 24, 60, and 36
Mariulka [41]
12 - all divisible by it (2*12=24, 3*12=36, 12*5=60)
3 0
3 years ago
Read 2 more answers
How many integers are there that consist of four digits (from 1000 to 9999) where the first digit is a 5 or an 8 and the third d
Ostrovityanka [42]

Answer:

1600 integers

Step-by-step explanation:

Since we have a four digit number, there are four digit placements.

For the first digit, since there can either be a 5 or an 8, we have the arrangement as ²P₁ = 2 ways.

For the second digit, we have ten numbers to choose from, so we have ¹⁰P₁ = 10.

For the third digit, since it neither be a 5 or an 8, we have two less digit from the total of ten digits which is 10 - 2 = 8. So, the number of ways of arranging that is ⁸P₁ = 8.

For the last digit, we have ten numbers to choose from, so we have ¹⁰P₁ = 10.

So, the number of integers that can be formed are 2 × 10 × 8 × 10 = 20 × 80 = 1600 integers

5 0
3 years ago
Evaluate if m=-6 what is m/2 + m =
love history [14]

Answer:

9

Step-by-step explanation:

they said that m=6 which you can plug in into the problem, now that you know what 'm' is. It will look like this:

6/2 + 6 = ?

6 divided by 2 = 3 so it'll look like this

3 + 6 = 9

7 0
2 years ago
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