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2 years ago

A square park is of side 100 m. A path 5 m wide is made all around the garden inside it. Find the area

Mathematics

2 answers:

MrRa [10]2 years ago

8 0

Answer:

I am assuming that the path is just around the square park. The area of the path is 1,900m².

Step-by-step explanation:

We first need to layout the path around the square park which is 5m in width.
Then, we have to divide the path into 4 areas.
Looking at the top view, let's assume that the left most part path is the Area 1 having a dimension of 100m x 5m.
The second area being the one at the top having a dimension of 95m x 5m.
The third area is the one on the left having a dimension of 95m x 5m.
And the last area is the one at the bottom having a dimension of 90m x 5m.

COMPUTATION:

$area \: 1 = 5(100) = 500 \\area \: 2 = 5(95) = 475 \\ area \: 3 = 5(95) = 475 \\ area \: 4 = 5(90) = 450 \\ \\ total \: area = 500 + 475 + 475 + 450 \\ = 1900 {m}^{2}$

mihalych1998 [28]2 years ago

3 0

Answer:

area's formula is length * breadth so 100*5

answer is 500m/s

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3 years ago

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storchak [24]

Answer:

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Step-by-step explanation:

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2 years ago

At a sport clubhouse the coach wants to rope off a rectangular area that is adjacent to the building. He uses the length of the

Furkat [3]

Answer:

w < 8 meters ( w must be greater than 0 because length cannot be 0)

Step-by-step explanation:

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3 years ago

A triangular playground has angles with measures in ratio 8: 3: 9 what is the measure of the smallest angle

maria [59]

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2 years ago

Read 2 more answers

An object is dropped from a small plane. As the object falls, its distance, d, above the ground after t seconds, is given by the

DedPeter [7]

The inequality can be used to find the interval of time taken by the object to reach the height greater than 300 feet above the ground is:

$d = -16t^2 + 1000$

Solution:

The object falls, its distance, d, above the ground after t seconds, is given by the formula:

$d = -16t^2 + 1000$

To find the time interval in which the object is at a height greater than 300 ft

Frame a inequality,

$-16t^2 + 1000 > 300$

Solve the inequality

Subtract 1000 from both sides

$-16t^2 + 1000 - 1000 > 300 - 1000\\\\-16t^2 > -700$

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Time cannot be negative

Therefore,

t < 6.61

And the inequality used is: $-16t^2 + 1000>300$

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2 years ago