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lana66690 [7]
2 years ago
7

I need help pleaseeeeeeeeeeeeeeeee!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
2 answers:
luda_lava [24]2 years ago
4 0
2/12 bc one of my classmate( A smart one answered but don’t explain so sorry if you need an explanation)
liq [111]2 years ago
3 0

Answer:

2/12

Step-by-step explanation:

You have to divide 2/3 by 4 which is the same as multiply 2/3 with 1/4.

This will give you 2/12

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What is the correct answer
nevsk [136]
The correct answer for this question is 4
8 0
3 years ago
Read 2 more answers
An item was bought for £50. It was sold for £32. What was the percentage loss?
kumpel [21]

Answer:

36% loss

Step-by-step explanation:

To calculate percentage loss

\frac{loss}{original} × 100%

loss = £50 - £32 = £18, then

percentage loss = \frac{18}{50} × 100% = 18 × 2 % = 36%

5 0
3 years ago
Read 2 more answers
Find the arc length of the partial circle.
Len [333]

Answer:

4.71

Step-by-step explanation:

Arc length = 2*pi*r-(pi*r)/2

Arc length = 3*2*(3.14)/4 = 4.71

6 0
3 years ago
Use completing the square to solve this quadratic equation.
borishaifa [10]

Step-by-step explanation:

x² + 6x + 9 = 2

(x + 3)² = 2

x + 3 = ±sqrt(2)

x = -3 ± sqrt(2)

so, B and D are correct.

control :

(-3 + sqrt(2))² + 6(-3 + sqrt(2)) + 9 = 2

9 + 2 - 6sqrt(2) - 18 + 6sqrt(2) + 9 = 2

2 = 2

correct

(-3 - sqrt(2))² + 6(-3 - sqrt(2)) + 9 = 2

9 + 2 + 6sqrt(2) - 18 - 6sqrt(2) + 9 = 2

2 = 2

correct

(3 + sqrt(2))² + 6(3 + sqrt(2)) + 9 = 2

9 + 2 + 6sqrt(2) + 18 + 6sqrt(2) + 9 = 2

38 + 12sqrt(2) = 2

wrong.

(3 - sqrt(2))² + 6(3 - sqrt(2)) + 9 = 2

9 + 2 - 6sqrt(2) + 18 - 6sqrt(2) + 9 = 2

38 - 12sqrt(2) = 2

wrong.

7 0
3 years ago
My teacher asked me me to round 343 to the nearest hundred. I think the answer is 300 but am not certain. Am I correct? Helping
Rashid [163]
It is the right answer, is it is 5 or more you add the number that you are supposed to round, but since the number next to it is 4, you can keep it the same and add the 0's. (I'm a kid, so sorry if there is misspells)
6 0
3 years ago
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