What are the answer to these? PLEASE ANSWER (don’t mind my work)

Mathematics

1 answer:

SSSSS [86.1K]3 years ago

5 0

uno is the answer i believe

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Ineed help help me please

melamori03 [73]

The symbol ₁₂P₉ represents the permutations of 9 quantities out of 12.
By definition,
$_{12}P_{9} = \frac{12!}{(12-9)!} = \frac{12!}{3!}$

From the calculator,
12! = 479,001,600
3! = 6

Therefore
₁₂P₉ = 479001600/6 = 79,833,600

Answer: 79,833,600

8 0

3 years ago

Solve -3.5 = for x using the multiplication property of equality. The operation in the problem is eration is Addition Subtractio

Gemiola [76]

The answer is the Division on the top The multiplication then -14

Step-by-step explanation: I hope this will help you

6 0

3 years ago

Help please

mrs_skeptik [129]

It will be 1.104 so i think it will be that ikd

6 0

3 years ago

Find 10 partial sums of the series. (round your answers to five decimal places.) ∞ 15 (−4)n n = 1

nikklg [1K]

Given

$\Sigma_{n=1}^\infty15(-4)^n$

The first 10 partial sums are as follows:

$S_1=\Sigma_{n=1}^{1}15(-4)^n=15(-4)=\bold{-60} \\ \\ S_2=\Sigma_{n=1}^{2}15(-4)^n=\Sigma_{n=1}^{1}15(-4)^n+15(-4)^2 \\ =-60+15(16)=-60+240=\bold{180} \\ \\ S_3=\Sigma_{n=1}^{3}15(-4)^n=\Sigma_{n=1}^{2}15(-4)^n+15(-4)^3 \\ =180+15(-64)=180-960=\bold{-780} \\ \\ S_4=\Sigma_{n=1}^{4}15(-4)^n=\Sigma_{n=1}^{3}15(-4)^n+15(-4)^4 \\ =-780+15(256)=-780+3,840=\bold{3,060} \\ \\ S_5=\Sigma_{n=1}^{5}15(-4)^n=\Sigma_{n=1}^{4}15(-4)^n+15(-4)^5 \\ =3,060+15(-1,024)=3,060-15,360=\bold{-12,300}$

$S_6=\Sigma_{n=1}^{6}15(-4)^n=\Sigma_{n=1}^{5}15(-4)^n+15(-4)^6 \\ =-12,300+15(4,096)=-12,300+61,440=\bold{49,140}$

The rest of the partial sums can be obtained in similar way.

7 0

3 years ago

Please help will mark brainliest

MA_775_DIABLO [31]

One number to the right of the decimal will mean there are two numbers to the left of the decimal.

When rounding to 50 as the nearest ten the number needs to be between 45 and 54.

Using the 3 numbers shown that would be 48.3

3 0

3 years ago