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Alona [7]
3 years ago
8

What's the area of this shape? Please answer. :) Tysm

Mathematics
1 answer:
lubasha [3.4K]3 years ago
6 0
If 52 ft. is one of your answers i would say 52, sorry if im wrong
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NEED HELP ASAP!!!!!!!!!!!!!!!!!!!!!!
Georgia [21]
The third table on the top row. It has a linear function because the Y is always constant. For example: -3 + -2= -5 -5 + -2= -7
7 0
3 years ago
Cuanto es 90 x 90 entre 50?
Sladkaya [172]
Tu respuesta Es 162
4 0
3 years ago
This is my next Trigonometry question I am needed help on- I just want to be sure I've got it right, or if not, then the steps I
makkiz [27]
\bf \textit{simmetry identities}\\\\
sin(-\theta)=-sin(\theta)\\\\
-------------------------------\\\\
sin(-\theta)=\cfrac{1}{5}\implies -sin(\theta)=\cfrac{1}{5}\implies sin(\theta)=\cfrac{-1}{5}\cfrac{\leftarrow opposite=b}{\leftarrow hypotenuse=c}
\\\\\\
c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a\implies \pm\sqrt{5^2-(-1)^2}=a
\\\\\\
\pm\sqrt{24}=a\implies \pm2\sqrt{6}=a

so. hmm which is it? the +/- ?   well, neverminding for a second, the value of tangent, just looking at the sign, the tangent is positive,

tangent = opposite/adjacent.... so that only happens, when both are the same sign, + or - both

now, we know the sine is -1/5.. if the sine is negative, the cosine also has t to be negative, so we'd use the -2√(6) = a

thus     \bf cos(\theta)=\cfrac{adjacent}{hypotenuse}\implies cos(\theta)=\cfrac{-2\sqrt{6}}{5}
4 0
3 years ago
Factor the following expression<br><br> 28w^(4)x^(2)y^(7)+12w^(9)x^(8)
disa [49]

The expression after factorisation is 4w⁴x² (7y⁷ + 3w⁵x⁶)

<h3>What is an Expression ?</h3>

An expression is defined as a mathematical statement consisting of variables , constants and mathematical operators.

The expression given is

28w⁴x²y⁷+12w⁹x⁸

Factors of the given expression will be the common terms in both the terms

w⁴x² is common in the variable term

The HCF of 28 and 12 is 4

4w⁴x² (7y⁷ + 3w⁵x⁶)

The expression after factorisation is 4w⁴x² (7y⁷ + 3w⁵x⁶)

To know more about Expression

brainly.com/question/14083225

#SPJ1

6 0
2 years ago
Find the number c that satisfies the conclusion of the Mean Value Theorem on the given interval. (Enter your answers as a comma-
ivanzaharov [21]

Answer:

c = \displaystyle\frac{9}{4}

Step-by-step explanation:

The following information is missing in the given question:

f(x) = \sqrt{x}

Using this we may solve the question as:

We are given the following in the question:

f(x) = \sqrt{x}, x \in [0,9]

We have to find the number c such that f(x) satisfies the Mean value theorem.

Mean Value theorem:

It states that if the function is differentiable in the closed interval [a,b], differentiable in the interval (a,b), then there exist c in (a,b) such that:

f'(c) = \displaystyle\frac{f(b)-f(a)}{b-a}

Now,

f(x) = \sqrt{x}\\f'(x) = \frac{1}{2\sqrt{x}}

Continuity in [0,9]

Since a polynomial function is continuous everywhere, f(x) is continuous in [0,9]

Differentiability in (0,9)

Since a polynomial function is differentiable everywhere the given function is differentiable in interval (0,9)

Then, by mean value theorem:

f'(c) = \displaystyle\frac{f(b)-f(a)}{b-a}\\\\\frac{1}{2\sqrt{c}} = \frac{f(9) - f(0)}{9-0} = \frac{3}{9}\\\\\frac{1}{2\sqrt{c}} = \frac{1}{3}\\\\c= \frac{9}{4}

7 0
3 years ago
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