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2 years ago

The graph of a function g is shown below.

Mathematics

1 answer:

Alecsey [184]2 years ago

4 0

Answer:

this is wrong

is the answer

if you like my answer please like comment and mark me as brilliant

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25^(x+2) = (1/5)^(4x)

dangina [55]

The first step for solving this equation is to write $25^{x+2}$ in exponential form with a base of 5.
$5^{2x+4}$ = $( \frac{1}{5}) ^{4x}$
Write $( \frac{1}{5}) ^{4x}$ in exponential form with a base of 5.
$5^{2x+4}$ = $5^{-4x}$
Since the bases on both sides of the equal are the same,, set the exponents equal.
2x + 4 = -4x
Move the constant to the right side of the equation and then change its sign.
2x = -4x - 4
Now move the variable to the left side and change its sign.
2x + 4x = -4
Collect the terms with an x variable.
6x = -4
Lastly,, divide both sides of the equation by 6 to get your final answer.
x = $- \frac{2}{3}$
Let me know if you have any further questions.
:)

8 0

3 years ago

4/16 in simplest form

vova2212 [387]

4 goes into 4 once, and then into 16 4 times. Making the final answer 1/4

6 0

3 years ago

Read 2 more answers

8 = 3a + 4...Anyone know the answer??

scoray [572]

Answer:

8 = 3a + 4

4=3a

4/3=a

hope this helps

have a good day :)

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

What does this graph represent?

grandymaker [24]

Answer:

I think its a car coming to a stop.

Step-by-step explanation:

As you can see with time, the speed decreases

5 0

4 years ago

Read 2 more answers

Exercise 7.3.5 The following is a Markov (migration) matrix for three locations        1 5 1 5 2 5 2 5 2 5 1 5 2 5 2 5 2

fredd [130]

Answer:

Both get the same results that is,

$\left[\begin{array}{ccc}140\\160\\200\end{array}\right]$

Step-by-step explanation:

Given :

$\bf M=\left[\begin{array}{ccc}\frac{1}{5}&\frac{1}{5}&\frac{2}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{1}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{2}{5}\end{array}\right]$

and initial population,

$\bf P=\left[\begin{array}{ccc}130\\300\\70\end{array}\right]$

a) - After two times, we will find in each position.

$P_2=[P].[M]^2=[P].[M].[M]$

$M^2=\left[\begin{array}{ccc}\frac{1}{5}&\frac{1}{5}&\frac{2}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{1}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{2}{5}\end{array}\right]\times \left[\begin{array}{ccc}\frac{1}{5}&\frac{1}{5}&\frac{2}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{1}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{2}{5}\end{array}\right]$

$=\frac{1}{25} \left[\begin{array}{ccc}7&7&7\\8&8&8\\10&10&10\end{array}\right]$

$\therefore\;\;\;\;\;\;\;\;\;\;\;P_2=\left[\begin{array}{ccc}7&7&7\\8&8&8\\10&10&10\end{array}\right] \times\left[\begin{array}{ccc}130\\300\\70\end{array}\right] = \left[\begin{array}{ccc}140\\160\\200\end{array}\right]$

b) - With in migration process, 500 people are numbered. There will be after a long time,

$After\;inifinite\;period=[M]^n.[P]$

$Then,\;we\;get\;the\;same\;result\;if\;we\;measure [M]^n=\frac{1}{25} \left[\begin{array}{ccc}7&7&7\\8&8&8\\10&10&10\end{array}\right]$

$=\left[\begin{array}{ccc}140\\160\\200\end{array}\right]$

4 0

3 years ago