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Naddik [55]
3 years ago
5

Help please quickly i need help

Mathematics
1 answer:
vekshin13 years ago
4 0

Answer:

-7/3 is c

-2.9 is a

-2 5/8 is b

Step-by-step explanation:

-5/2 = -2.5

-7/3 > -2.5, so -7/3 is c

-6/2 = -3

-2.9 is very close to -3, so -2.9 is a

-2 5/8 is just a little less that -2.5, so -2 5/8 is b

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In order to find this, get all w values to the right side and all numbers to the left side.

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-2.27 + 10.4w = -3.4w - 17.45 ----> add 3.4w to both sides

-2.27 + 13.8w = -17.45 ----> add 2.27 to both sides

13.8w = -15.18 -----> divide both sides by 13.8

w = -1.1

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3 years ago
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A sphere has a radius of 12 inches. A second sphere has a radius of 9 inches. What is the difference of the volumes of the spher
just olya [345]

Answer:

Solution given;

for sphere

radius [r]:12inches

another

radius [R]:9inches

Now

difference in volume of sphere:

volume of sphere of having radius [r-R]

=\frac{4}{3} πr³-\frac{4}{3} πR³

=\frac{4}{3} π(12³-9³)

= 1332π cubic inches

The volume of the larger sphere is <u>___1332</u>__π cubic inches greater than the volume of the smaller sphere.

3 0
3 years ago
Find the slope of the line passing through each of the following pairs of points and draw the graph of the line.
tiny-mole [99]

Answer:

The slope is 1/2

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

i am very very shmart

8 0
3 years ago
The sum of squares of two consecutive odd numbers is 514 find the numbers ​
amid [387]

Correct Question : The sum of squares of two consecutive positive odd numbers is 514. Find the numbers.

\rule{130}1

Solution :

Let the two consecutive positive odd numbers be x and (x + 2)

\rule{130}1

☯ \underline{\boldsymbol{According\: to \:the\: Question\:now :}}

:\implies\sf x^2 + (x + 2)^{2} = 514 \\\\\\:\implies\sf x^2 + x^2 + 4x + 4 = 514\\\\\\:\implies\sf 2x^2 + 4x + 4 = 514 \\\\\\:\implies\sf 2x^2 + 4x = 514 - 4\\\\\\:\implies\sf 2x^2 + 4x = 510 \\\\\\:\implies\sf 2x^2 + 4x - 510 = 0\\\\\\:\implies\sf x^2 + 2x - 255 = 0 \:\:\:\:\:\Bigg\lgroup \bf{Dividing\:by\:2}\Bigg\rgroup\\\\\\:\implies\sf x^2 + 17x - 15x - 255 = 0\\\\\\:\implies\sf x(x + 17) - 15(x + 17) = 0\\\\\\:\implies\sf (x + 17) (x - 15)\\\\\\:\implies\sf x = - 17\:or\:x = 15\\\\\\:\implies\underline{\boxed {\sf x = 15}}\:\:\:\:\:\Bigg\lgroup \bf{Positive\:odd\: number}\Bigg\rgroup

When,

\bullet\: \textsf {x = } \textbf {15}

\bullet\: \sf x + 2 = 15 + 2 =\textbf{ 17}

\therefore\:\underline{\textsf{The required positive integer is \textbf{15 and 17}}}.

5 0
3 years ago
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