The area of square is
square units
<h3><u>Solution:</u></h3>
Given that square has side length (x+5) units
To find: area of square
<em><u>The area of square is given as:</u></em>
![\text {Area of square }=\mathrm{a}^{2}](https://tex.z-dn.net/?f=%5Ctext%20%7BArea%20of%20square%20%7D%3D%5Cmathrm%7Ba%7D%5E%7B2%7D)
Where "a" is the length of side
From question, length of each side "a" = x + 5 units
Substituting the value in above formula,
![\text {Area of square }=(x+5)^{2}](https://tex.z-dn.net/?f=%5Ctext%20%7BArea%20of%20square%20%7D%3D%28x%2B5%29%5E%7B2%7D)
![{\text {Expanding }(x+5)^{2} \text { using the algebraic identity: }} \\\\ {(a+b)^{2}=a^{2}+2 a b+b^{2}}\end{array}](https://tex.z-dn.net/?f=%7B%5Ctext%20%7BExpanding%20%7D%28x%2B5%29%5E%7B2%7D%20%5Ctext%20%7B%20using%20the%20algebraic%20identity%3A%20%7D%7D%20%5C%5C%5C%5C%20%7B%28a%2Bb%29%5E%7B2%7D%3Da%5E%7B2%7D%2B2%20a%20b%2Bb%5E%7B2%7D%7D%5Cend%7Barray%7D)
![\begin{array}{l}{\text {Area of square }=x^{2}+2(x)(5)+5^{2}} \\\\ {\text {Area of square }=x^{2}+10 x+25}\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bl%7D%7B%5Ctext%20%7BArea%20of%20square%20%7D%3Dx%5E%7B2%7D%2B2%28x%29%285%29%2B5%5E%7B2%7D%7D%20%5C%5C%5C%5C%20%7B%5Ctext%20%7BArea%20of%20square%20%7D%3Dx%5E%7B2%7D%2B10%20x%2B25%7D%5Cend%7Barray%7D)
Thus the area of square is
square units
Answer:
x just represents a number
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