What is the mad of these set of numbers- 0,0,0,0,0,0,1,1,1,1,1,1,2,2,2,2,2,2,2,3,4,4
matrenka [14]
I got .991. The mean was 1.4 so I subtracted 1.4 from each number even if I had to do it more than once. I took the absolute value of each number and added them. The sum was 21.8. I then divided 21.8 by 22 and got .99090(90 repeated)
<u>Answer with explanation:</u>
As per given , we have
A sample of 50 gribbles finds an average length of 3.1 mm with a standard deviation of 0.72.
i.e. n= 50
Degree of freedom = n-1=49


The point estimate of the population mean is equals to the sample mean.
i.e. The best estimate for the length of gribbles= 3.1 mm
Also, population standard deviation is unknown , then the confidence interval would be :

For df= 49 and significance level of 0.05 , the t- value (using t-distribution table) would be :

Now, Margin of error : 

95% confidence interval : 

Answer:
X= - 12/7 i hope it is helpful have a nice day if you want steps i will show you
Answer:
<
Step-by-step explanation:
-17 < -1
Answer:
10
Step-by-step explanation: