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Alex17521 [72]
3 years ago
9

What is 3185 divided by 1625?

Mathematics
1 answer:
Vinil7 [7]3 years ago
5 0

Answer:

1,96

Step-by-step explanation:

= 3185 ÷ 1625

= 1,96

#off

#thankyou:))

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Given that CD¯¯¯¯¯¯¯¯ is a perpendicular bisector of AB¯¯¯¯¯¯¯¯, where D is on AB¯¯¯¯¯¯¯¯, how can you use the Pythagorean Theor
Liula [17]

Answer:

(AD)^2 + (CD)^2 = (CA)^2 and (CD)^2 + (BD)^2 = (CB)^2

Step-by-step explanation:

Given

Bisector: CD

of Line AB

Required

Apply Pythagoras Theorem

From the question, CD bisects AB and it bisects it at D.

The relationship between AB and CD is given by the attachment

Considering ACD

From the attachment, we have that:

Hypothenuse = CA

Opposite = CD

Adjacent = AD

By Pythagoras Theorem, we have

(AD)^2 + (CD)^2 = (CA)^2

Considering CBD

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Hypothenuse = CB

Opposite = CD

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By Pythagoras Theorem, we have:

(CD)^2 + (BD)^2 = (CB)^2

4 0
3 years ago
Read 2 more answers
If g (x) = 1/x then [g (x+h) - g (x)] /h
lys-0071 [83]

Answer:

\dfrac{-1}{x(x+h)}, h\ne 0

Step-by-step explanation:

If g(x) = \dfrac{1}{x}, then g(x+h) = \dfrac{1}{x+h}. It follows that

  \begin{aligned} \\\frac{g(x+h)-g(x)}{h} &= \frac{1}{h} \cdot [g(x+h) - g(x)] \\&= \frac{1}{h} \left( \frac{1}{x+h} - \frac{1}{x} \right)\end{aligned}

Technically we are done, but some more simplification can be made. We can get a common denominator between 1/(x+h) and 1/x.

  \begin{aligned} \\\frac{g(x+h)-g(x)}{h} &= \frac{1}{h} \left( \frac{1}{x+h} - \frac{1}{x} \right)\\&=\frac{1}{h} \left(\frac{x}{x(x+h)} - \frac{x+h}{x(x+h)} \right) \\ &=\frac{1}{h} \left(\frac{x-(x+h)}{x(x+h)}\right) \\ &=\frac{1}{h} \left(\frac{x-x-h}{x(x+h)}\right) \\ &=\frac{1}{h} \left(\frac{-h}{x(x+h)}\right) \end{aligned}

Now we can cancel the h in the numerator and denominator under the assumption that h is not 0.

  = \dfrac{-1}{x(x+h)}, h\ne 0

5 0
3 years ago
Need some help with this photo it would be much appreciated :)
masya89 [10]

Answer:

12.6

Step-by-step explanation:

c=2 x 3.14 x r

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6.28 x 2= 12.56

4 0
3 years ago
While watching a parade I saw some clowns and horses. I counted 30 legs and 10 heads. How many horses did I see in the parade?
emmasim [6.3K]
The answer is 5 horses
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4 years ago
Subtract 14pqr − 2qrs + 10prs from 6pqr - 5qrs - 7prs<br><br> Help needed and quick!!!!!!
love history [14]

Answer:

- 8pqr - 3qrs - 17prs

Step-by-step explanation:

(6pqr - 5qrs - 7prs) - (14pqr − 2qrs + 10prs) = (6pqr - 14pqr) + (-5qrs - - 2qrs) + (-7prs - 10prs)

= - 8pqr - 3qrs - 17prs

7 0
3 years ago
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