Let the area of the original rectangle be A₁.
A₁ = (12 ft)(8 feet) = 96 ft²
To determine the area of the reduced triangle, let's compute the new dimensions first.
Length = 12 ft * 3/4 - 9 ft
Width = 8 ft *3/4 = 6 ft
Thus, the area of the new rectangle denoted as A₂ is
A₂ = (9 ft)(6 ft) = 54 ft
The ratio of the areas are:
A₂/A₁ = 54/96 = 9/16
The ratio of the sides are given to be 3/4.
Finally the ratios of the area to side would be:
Ratio = 9/16 ÷ 3/4 = 3/4
Therefore, the ratio of the areas is 3/4 of the ratio of the corresponding sides.
Answer:
43.3
Step-by-step explanation:
45-5=40,
0.0825*40=3.3
40+3.3=43.3
(x , y) = (7, - 1)
2x + 3y = 11 → (1)
3x + 3y = 18 → (2)
subtracting (1) from (2) term by term eliminates the y- term
(3x - 2x) + (3y - 3y) = (18 - 11)
x + 0 = 7 ⇒ x = 7
substitute x = 7 into either of the 2 equations and solve for y
(1) → (2 × 7) + 3y = 11
14 + 3y = 11
subtract 14 from both sides
3y = 11 - 14 = - 3
divide both sides by 3
= - 1
solution is (7 , -1)
Cut it up
3.
left rectangle and right rectangle
left recgnale is 2 height, 3 width 6 legnth
V=6*3*2=36
right rectangle is 2 height 2 width and 4 legnth
V=4*2*2=16
add them 36+16=52ft^2
5. we can't se how widt the small right side is because you didn't capture that
Answer:
Alright just add fractions, find the LCD and then combine
53 Hope this helps. :)
Step-by-step explanation:
