3 years ago

Help asap please!!

Mathematics

1 answer:

djverab [1.8K]3 years ago

4 0

Answer:

Step-by-step explanation:

The common ratio = 100/500 = 1/5 and the first term a1 = 500.

The rule is a1=500; an = 1/5a(n-1)

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TV−→− bisects ∠RTS. If the m∠RTV=(16x−6)° and m∠VTS=(13x+9)° , what is the value of x and the m∠RTV ?

natta225 [31]

Answer:

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Step-by-step explanation:

Given

$RTV=16x - 6$

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Required

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Since, TV is a bisector, then

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and

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Substitute values of RTV and VTS in (2)

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