Question

The population of a certain single-cell organism doubles every hour, starting with 100 cells. Which COULD be an equation to model this situation, where f(t) is the number of organisms and t is time in hours

Answer 1

Answer:

$f(t)=100e^{0.6931t}$

Step-by-step explanation:

The initial number of cells = 100 and it doubles every hour.

Let the exponential function be

$A=Pe^{rt}$

In 1 hour, A = 2P

$2P=Pe^{r\cdot1}\\\\2=e^r\\\\r=\ln2\\\\r=$

Therefore, the model of the given situation is given by

$f(t)=100e^{0.6931t}$