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3 years ago

TV−→− bisects ∠RTS. If the m∠RTV=(16x−6)° and m∠VTS=(13x+9)° , what is the value of x and the m∠RTV ?

Mathematics

1 answer:

natta225 [31]3 years ago

8 0

Answer:

$x = 5$

$RTV = 74$

Step-by-step explanation:

Given

$RTV=16x - 6$

$VTS=13x+9$

Required

Determine the values of x and RTV

Since, TV is a bisector, then

$RTS = RTV + VTS$ --- (1)

and

$RTV = VTS$ -- (2)

Substitute values of RTV and VTS in (2)

$16x - 6 = 13x + 9$

Collect Like Terms

$16x - 13x = 9 + 6$

$3x = 15$

Solve for x

$x = 5$

Substitute 5 for x in $RTV=16x - 6$

$RTV = 16 * 5 - 6$

$RTV = 80 - 6$

$RTV = 74$

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