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frez [133]
3 years ago
7

TV−→− bisects ∠RTS. If the m∠RTV=(16x−6)° and m∠VTS=(13x+9)° , what is the value of x and the m∠RTV ?

Mathematics
1 answer:
natta225 [31]3 years ago
8 0

Answer:

x = 5

RTV = 74

Step-by-step explanation:

Given

RTV=16x - 6

VTS=13x+9

Required

Determine the values of x and RTV

Since, TV is a bisector, then

RTS = RTV + VTS --- (1)

and

RTV = VTS -- (2)

Substitute values of RTV and VTS in (2)

16x - 6 = 13x + 9

Collect Like Terms

16x - 13x = 9 + 6

3x = 15

Solve for x

x = 5

Substitute 5 for x in RTV=16x - 6

RTV = 16 * 5 - 6

RTV = 80 - 6

RTV = 74

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