What is the area of this quadrilateral? 2 ft 3 ft 8 ft 8 ft 3 ft 2 ft

27. Solve for x? A 25 B 16 C 27 D 9

musickatia [10]

I’m not really sure but if I did it correctly I’m pretty sure it’s c.27

8 0

3 years ago

Find x. A. 21√2 B. 7 C. 21√3 over 2 D. 21√2 over 2

kkurt [141]

Answer:

D

Step-by-step explanation:

for you to find x you first have to find the adjacent of the 45° angle you can do that by using the other triangle.using the sin ratio

sin60=opposite/hypotenuse

sin60=a/7√3

a=10.5

then after you have found the adjacent you can use the cos ratio

cos45=adjacent/hypotenuse

cos45=10.5/x

cos45x/cos45=10.5/cos45

x=14.849

which is the same as 21√2 over 2

I hope this helps

5 0

3 years ago

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What ratios are equivalent to 3/5

barxatty [35]

The given ratios 3: 5 and 15: 25 are equal. Because when you divide the ratio 15: 25 by 5 on both numerator and denominator, the first ratio 3: 5 can be obtained. Similarly, when you multiply the first ratio 3: 5 by 5, the ratio 15: 25 can be obtained.

5 0

3 years ago

What is the area of the figure:

Luba_88 [7]

For this case we have that the area of the triangle is given by:

$A = \frac {b * h} {2}$

Where:

b: It's the base

h: It's the height

We have to:

$cos (45) = \frac {b} {24}\\b = 24 * cos (45)\\b = \frac {\sqrt {2}} {2} * 24\\b = 12 \sqrt {2}$

The atura will be given by:

$sin (45) = \frac {h} {24}\\h = 24 * sin (45)\\h = \frac {\sqrt {2}} {2} * 24\\h = 12 \sqrt {2}$

So, the area is:

$A = \frac {12 \sqrt {2} * 12 \sqrt {2}} {2}\\A=\frac{(12\sqrt{2})^2}{2}\\A = 144$

Answer:

144

6 0

3 years ago

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A coin is tossed. If head appears, A spinner that can land on any number from 1 to 4 is spun. if tales appears a second coin is

kramer

The answer is c because if head appears and the spinner is spun with 1 - 4 on it then you can get either h1, h2, h3 or h4 and if tales appears and another coin is tossed you can get either th or tt

5 0

3 years ago