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Georgia [21]
3 years ago
13

Bert already has $50 but needs a total of at least $250 for his holiday. He gets paid $20 per day for delivering papers. What is

the least number of days he must work to get enough money for his holiday
Mathematics
1 answer:
Lana71 [14]3 years ago
3 0
50+20x=250
-50. -50

20x=200

Divide both sides by 20
X=10
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Allie hits the ball 45% of the time
solong [7]

Answer:36 times hope it helps

Step-by-step explanation:

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△FSB∼△ZDR .<br><br> What is the value of x?<br><br> Enter your answer.<br><br> How many units?
kari74 [83]
Answer: 22

---------------------------------------------------------

Explanation:

The triangles are similar, so we know the corresponding sides form ratios that are equal. 

Note how...
FS and ZD are the first two letters of FSB and ZDR respectively
FB and ZR are the first & last letters of FSB and ZDR respectively

Based on those two facts above, we can form this proportion
FS/ZD = FB/ZR
38/15.2 = 55/x

Solve for x
38/15.2 = 55/x
38*x = 15.2*55
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4 0
3 years ago
The answer to B and C
ArbitrLikvidat [17]
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3 0
3 years ago
Algebra 2 help please! I thought i got this one right but it’s wrong.
daser333 [38]

Answer:

area = 6x^2+10x-4 perimeter= 5x+3

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
There are 15 identical pens in your drawer, nine of which have never been used. On Monday, yourandomly choose 3 pens to take wit
DaniilM [7]

Answer: p = 0.9337

Step-by-step explanation: from the question, we have that

total number of pen (n)= 15

number of pen that has never been used=9

number of pen that has been used = 15 - 9 =6

number of pen choosing on monday = 3

total number of pen choosing on tuesday=3

note that the total number of pen is constant (15) since he returned the pen back .

probability of picking a pen that has never been used on tuesday = 9/15 = 3/5

probability of not picking a pen that has never been used on tuesday = 1-3/5=2/5

probability of picking a pen that has been used on tuesday = 6/15 = 2/5

probability of not picking a pen that has not been used on tuesday= 1- 2/5= 3/5

on tuesday, 3 balls were chosen at random and we need to calculate the probability that none of them has never been used .

we know that

probability of ball that none of the 3 pen has never being used on tuesday = 1 - probability that 3 of the pens has been used on tuesday.

to calculate the probability that 3 of the pen has been used on tuesday, we use the binomial probability distribution

p(x=r) = nCr * p^{r} * q^{n-r}

n= total number of pens=15

r = number of pen chosen on tuesday = 3

p = probability of picking a pen that has never been used on tuesday = 9/15 = 3/5

q = probability of not picking a pen that has never been used on tuesday = 1-3/5=2/5

by slotting in the parameters, we have that

p(x=3) = 15C3 * (\frac{2}{5})^{3} * (\frac{3}{5})^{12}

p(x=3) = 455 * 0.4^{3} * 0.6^{12}

p(x=3) = 455 * 0.064 * 0.002176

p(x=3) = 0.0633

thus probability that 3 of the pens has been used on tuesday. = 0.0633

probability of ball that none of the 3 pen has never being used on tuesday  = 1 - 0.0633 = 0.9337

3 0
3 years ago
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