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Fittoniya [83]
2 years ago
9

Why Do Onions Make You Cry? Even better, know how to prevent the tears.

Chemistry
2 answers:
erastovalidia [21]2 years ago
5 0

Answer:

The onion cells release compounds into the air, and enzymes must follow up to alter amino acids into other compounds, causing irritation in the eye. To prevent, "crying" from an onion, try peeling the onion, then chilling the onion in the fridge for about 30 minutes. Otherwise, you can buy tearless onions.

antoniya [11.8K]2 years ago
4 0

Answer: Allicin is extraordinarily risky and, as quickly as it is produced, allicin movements through the air, reaches the membrane on our eyes, and irritates it. In response, our eyes secrete tears to clean away the allicin and we start to cry and smart.

Explanation:

You might be interested in
At constant temperature, when the volume of a gas is decreased, what happens to its pressure? Select one: a. It increases. b. It
natulia [17]

Answer:

The answer would be

a. it increases

3 0
3 years ago
Prepare 10.00 mL of 0.010 M NaOH by diluting the NaOH solution used in Trial 1. (Your procedure should clearly show your calcula
denis-greek [22]

Answer:

<em> = 0.2 mL.</em>

Explanation:

Given a 0.5 M solution of NaOH as stock solution, 10.0mL of 0.010M can be prepared via dilution with distilled water, by using the formula:

C_{1} V_{1} = C_{2} V_{2}

where C1 and V1 are initial concentration and volume respectively; same as C2 & V2 for fina.

Let C1 = 0.5M, V2 = ?

C2 = 0.010M; V2 = 10mL

⇒Volume of stock solution to be diluted, V2

= \frac{10}{0.5} × 0.010

<em> = 0.2 mL.</em>

Glasswares used would be pipette (for smaller volume experiment) and measuring cylinder. 0.2mL would be measured and then made upto the 10mL mark of the measuring cylinder.

I hope this was a detailed explanation given the missing details of "Trial 1" in the question.

3 0
3 years ago
The standard length of a certain golf club is 116.84 cm. You measure the club to be 116.85 cm long. You measure it again and fin
IgorC [24]

Answer:

The first measurement is 116.84 cm, and the second measurement is 116.85 cm.

Explanation:

The problem provides both the first and second measurements so all you have to do is fill in the blank with them.

8 0
3 years ago
CO2+2H2O=H3O^++HCO3^-
bekas [8.4K]

<u>Answer:</u>

<em>Bronsted Lowry Theory</em>

<em>CO_2 is the acid </em>

<em>H_2 O is the base </em>

<em>H_3 O^+ is the conjugate acid and </em>

<em>HCO_3^- is the conjugate base</em>

<u>Explanation:</u>

Bronsted Lowry Theory:

An acid is a substance that can donate one or more protons

A base is a substance which can accept one or more protons

Hydrogen atom which is neutral (No Charge) contains 1 positive proton, 1 negative electron and 0 neutral neutron.  

Thus Hydrogen atom has no Charge and it is neutral.

When an hydrogen atom loses an electron, Hydrogen ion is formed, which will contain 1 positive proton and 0 negative electron and 0 neutral neutron.

Thus Hydrogen ion has a positive charge.  

Hydrogen ion is also called as a proton since it has only 1 proton in it.

Hydrogen ion in water that is,  

H^++H_2O\Rightarrow H_3O^+

H_3O^+ is called as Hydronium ion.

Acid loses H+ (proton) to form conjugate Base

Base gains H+ (proton) to form conjugate Acid

For example  

Let us consider the example given in the question

CO_2+2H_2 O>H_3 O^+   +HCO_3^- can be written as (removed 1 H_2 O from both the sides )

CO_2+H_2 O>H^++HCO_3^- or  

CO_2+H_2 O  > H_2 CO_3 reversing the equation  

H_2 CO_3+H_2 O>H_3 O^+  +HCO_3^-

H_2 CO_3 is the acid which donates H^+ to form HCO_3^-

H_2 O is the base which gains H^+ to form H_3 O^+

HCO_3^- is the conjugate base and H_3 O^+ is the conjugate acid

So

CO_2 is the acid

H_2 O is the base

H_3 O^+ is the conjugate acid and

HCO_3^- is the conjugate base

(Answer)  

5 0
3 years ago
Which of the following statements is true?
dybincka [34]
The correct answer is C. Atoms are incredibly small and can bearly be seen with the most powerful electron microscopes. The nucleas of an atom contains protons and neutrons with electrons in orbitals around the nucleas. I hope this helps. Let me know if anything is unclear.
3 0
3 years ago
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