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Komok [63]
3 years ago
10

Which statement describes a positive effect of selective breeding? A. Some desirable traits in a population can disappear. B. Of

fspring can be prone to genetic diseases. C. Parents can pass on useful traits to offspring, D. A population can end up with a lack of genetic diversity .​
Chemistry
2 answers:
-BARSIC- [3]3 years ago
8 0

Answer:

C. Parents can pass on useful traits to offspring

Explanation:

Brums [2.3K]3 years ago
8 0

Answer:

The Answer is C

Explanation:

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I need help with this ASAP PLEASE
Artemon [7]

439.3 g CO2

Explanation:

First find the # of moles of CO2 that results from the combustion of 3.327 mol C3H6:

3.227 mol C3H6 × (6 mol CO2/2 mol C3H6)

= 9.981 mol CO2

Use the molar mass of CO2 to determine the # of grams of CO2:

9.981 mol CO2 x (44.01 g CO2/1 mol CO2)

= 439.3 g CO2

5 0
3 years ago
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ANEK [815]
Parietal love
DND dnd
3 0
4 years ago
If 455 J of heat is transferred to 25.0g of water at 45.0 degrees Celsius, what is the final temperature of the water?
masya89 [10]

Answer:49.3

Explanation:4.1j/g c * 25g * (t2-45c)=455j

T2-45c = 455j/4.1j/g c * 25g

455/104.6

45+4.3= 49.3 celsius

3 0
3 years ago
Nitrogen gas at 300 k and 200 kpa is throttled adiabatically to a pressure of 100 kpa if the change in kinetic energy is negligb
erastovalidia [21]

Answer:

The temperature of the Nitrogen after throttling is  T_2 = 300 \  K

Explanation:

From the question we are told that

   The  temperature is  T_1 =  300 \  K

    The pressure is  P =  200 \  kPa  =  200 * 10^{3} \  Pa

    The pressure after being  P_1 =  100 \  kPa =  100 * 10^{3} \  Pa

   

Generally from the first law of thermodynamics we have that

      Q - W =  \Delta U + \Delta  K

Here \Delta U  is the change internal  energy which is mathematically represented as

            \Delta U =  C_p  (T_2 - T_1)

Here      C_p is the specific heat of the gas at constant pressure

        \Delta K  is the change kinetic energy which is negligible

         Q  is the thermal  energy  which is Zero for an adiabatic process

         W  is the work done and the value is zero given that the gas was throttled adiabatically

So

      0=  \Delta U +0

=>   \Delta U  = 0

=>  (T_2 - 300)  = 0

=>   T_2 = 300 \  K

     

3 0
3 years ago
Hydrogen is manufactured on an industrial scale by this sequence of reactions:
UNO [17]

Answer:

Explanation:

CH₄ +  H₂O(g)    ⇒ CO(g)+3H2(g)

Equilibrium constant

K₁ = [CO][H₂]³ / [CH₄][H₂O]

CO(g)+H₂O(g) ⇒ CO₂(g) + H₂(g)

Equilibrium constant

K₂ =  [CO₂][H₂] / [CO][H₂O]

CH₄(g)+2H₂O(g)  ⇒  CO₂(g)+4H₂(g)

Equilibrium constant

K =   [CO₂][H₂]⁴ /[CH₄][H₂O]²

=  [CO][H₂]³ / [CH₄][H₂O] X [CO₂][H₂] / [CO][H₂O]

K₁ x K₂

K = K₁ x K₂

4 0
3 years ago
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