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qwelly [4]
3 years ago
7

Lab report on physical and chemical change

Chemistry
1 answer:
Fynjy0 [20]3 years ago
4 0

That chemical change is : burning
Physical change: purple shirt
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Two samples of matter differ in temperature by 20°C. What is the difference in temperature of these two samples using the Kelvin
anyanavicka [17]

Answer:

The difference is 293.15 Kelvin.

Explanation:

Given data:

Temperature difference of matter = 20°C

Temperature difference of matter in kelvin = ?

Solution;

Formula:

0°C +273.15

now we will put the values instead of 0.

20°C + 273.15 = 293.15 K

Thus, the temperature difference between two sample is 293.15 K.

5 0
3 years ago
can someone please help me with these questions? predicting products and balancing the equations of single replacement​
FinnZ [79.3K]
Put the metal with the non-metal and use the charges to figure it out
4 0
3 years ago
Name three uses of satellite that effect every day?
fomenos
GPS- Global Positioning System, this is be found in cars
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Phone calls and text messages- the signals go from your phone to the satellite and back down to whoever you're texting.

Hope this helps :)
8 0
3 years ago
1) If you have 2.6 moles of iron (III) oxide, how many molecules of iron (III)
Ugo [173]

Answer:

234

Explanation:

so 3 x 3 x 26 =234

8 0
3 years ago
4. How many grams of ammonium carbonate are needed to decompose in order to produce
Thepotemich [5.8K]

Answer:

14.23g of (NH4)2CO3

Explanation:

We'll begin by writing the balanced equation for the reaction.

(NH4)2CO3 –> (NH4)2O + CO2

Next,, we shall determine the mass of (NH4)2CO3 that decomposed and the mass of CO2 produced from the balanced equation. This is illustrated below:

Molar mass of (NH4)2CO3 = 2[14+(4x1)] + 12 + (16x3)

= 2[14 +4] + 12 + 48

= 2[18] + 60 = 96g/mol

Mass of (NH4)2CO3 from the balanced equation = 1 x 96 = 96g

Molar mass of CO2 = 12 + (2x16) = 44g/mol

Mass of CO2 from the balanced equation = 1 x 44 = 44g.

Summary:

From the balanced equation above,

96g of (NH4)2CO3 decomposed to produce 44g of CO2.

Finally, we can determine the mass of (NH4)2CO3 that decomposed to produce 6.52g of CO2 as follow:

From the balanced equation above,

96g of (NH4)2CO3 decomposed to produce 44g of CO2.

Therefore, Xg of (NH4)2CO3 will decompose to produce 6.52g of CO2 i.e

Xg of (NH4)2CO3 = (96 x 6.52)/44

Xg of (NH4)2CO3 = 14.23g

Therefore, 14.23g of (NH4)2CO3 is needed to produce 6.52g of CO2.

4 0
3 years ago
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