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Vika [28.1K]
2 years ago
7

Approximate square root 18 to the nearest hundredth. Be sure to show all of your work.​

Mathematics
2 answers:
Vlad [161]2 years ago
8 0

Answer:

4.24 (nearest hundredth)

Step-by-step explanation:

<u>Step 1</u>

Square numbers: 1, 4, 9, 16, 25, 36, ...

Find the perfect squares either side of 18:

  • 16 and 25

As \sf \sqrt{16}=4 and \sf \sqrt{25}=5 then \sf 4 < \sqrt{18} < 5

<u>Step 2</u>

Divide 18 by one of the two square roots in step 1 (4 or 5):

⇒ 18 ÷ 4 = 4.5

<u>Step 3</u>

Find the average of the root (4) and the result (4.5):

\sf \implies \dfrac{4+4.5}{2}=4.25

<u>Repeat steps 2 and 3</u>:

Divide 18 by the solution of step 3.  Then find the average of this and the solution of step 3:

⇒ 18 ÷ 4.25 = 72/17

\sf \implies \dfrac{4.25+\frac{72}{17}}{2}=\dfrac{577}{136}=4.242647059

<u>Repeat</u>:

⇒ 18 ÷ 577/136 = 2448/577

\sf \implies \dfrac{\frac{577}{136}+\frac{2448}{577}}{2}=4.242640687

As the approximate square root needs to be to the nearest hundredth, we do not need to keep repeating the steps.

Therefore, √18 ≈ 4.24 (nearest hundredth)

Sladkaya [172]2 years ago
4 0

Answer:

The square root of 18 with one digit decimal accuracy is 4.2.

Step-by-step explanation:

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