Answer:
80,00
Step-by-step explanation:
According to my research, the formula for the Area of a rectangle is the following,

Where
- A is the Area
- L is the length
- W is the width
Since the building wall is acting as one side length of the rectangle. We are left with 1 length and 2 width sides. To maximize the Area of the parking lot we will need to equally divide the 800 ft of fencing between the <u>Length and Width.</u>
800 / 2 = 400ft
So We have 400 ft for the length and 400 ft for the width. Since the width has 2 sides we need to divide 60 by 2.
400/2 = 200 ft
Now we can calculate the maximum Area using the values above.


So the Maximum area we are able to create with 800 ft of fencing is 80,00
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The answer would be 3x - 5
Hope this helps!!!
2x = 119-15
2x= 104
x = 52
Answer:
x=5, y=4, z=3
Step-by-step explanation:
3x+2y+z=26
x=4y-11
then 3(4y-11)+2y+z=26, then
14y+z=59
by third part 2x=13-z=2(4y-11)=8y-22
8y+z=35
now we have 2 equations with y,z
14y+z-(8y+z)=59-35=24
6y=24
y=4
x=4y-11=4×4-11=5
z=13-2x=13-2(5)=3