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8_murik_8 [283]
3 years ago
6

-2x-y=-9 5x-2y=18 substitution

Mathematics
2 answers:
KIM [24]3 years ago
6 0
-2x-y=-9 \\
5x-2y=18 \\ \\
\hbox{solve the first equation for y:} \\
-2x-y=-9 \ \ \ |+2x \\
-y=-9+2x \ \ \ |\times (-1) \\
y=9-2x \\ \\
\hbox{substitute 9-2x for y in the second equation:} \\
5x-2(9-2x)=18 \\
5x-18+4x=18 \\
9x-18=18 \ \ \ |\div 9 \\
x-2=2 \ \ \ |+2 \\
x=4 \\ \\
y=9-2x=9-2 \times 4=9-8=1 \\ \\
\boxed{(x,y)=(4,1)}
Inessa05 [86]3 years ago
4 0
-2x-y = -9 5x-2y=18 -solve for y in terms of x -y= 2x-9 y=-2x+9 substitute 5x-2 ( -2x+9)=18 5x+4x -18=18 9x-18=18 9x= 36 x=4 substitute for x -2 (4) -y= -9 -8 -y = -9 -y = -1 y= 1 ANSWER x= 4 y=1 hope this helps
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5(x+2)=6x+3x-14 please solve
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Answer:

5(x+2)=6x+3x−14

Step 1: Simplify both sides of the equation.

5(x+2)=6x+3x−14

(5)(x)+(5)(2)=6x+3x+−14(Distribute)

5x+10=6x+3x+−14

5x+10=(6x+3x)+(−14)(Combine Like Terms)

5x+10=9x+−14

5x+10=9x−14

Step 2: Subtract 9x from both sides.

5x+10−9x=9x−14−9x

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Step 3: Subtract 10 from both sides.

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Step 4: Divide both sides by -4.

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