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1 year ago

Pleasee help I would appreciate very!

Mathematics

1 answer:

Yuki888 [10]1 year ago

8 0

Answer:

Step-by-step explanation:

We can visually see the line going down so the slope is negative. (-30)

The y-intercept must be 120, because it does not intersect 90.

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What is the quotient of 9−x^2 divided by 3x and x^2+6x+9 divided by 3x?

Naddik [55]

Answer:

44 rem

Step-by-step explanation:

Sorry i dont have an explanation

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2 years ago

is the equation a true statement when x equals -3 in other words is -3 a solution to the equation 6 x + 5 = 5x +8 + 2x explained

serg [7]

Answer: Yes

Step-by-step explanation: bc 6(-3)+5=5(-3)+8+2(-3)

Becomes -18+5=-15+8+-6 which equals -13 on both sides meaning -3 is a solution

5 0

2 years ago

Read 2 more answers

Question 1

Shkiper50 [21]

Answer:

Let's begin with a 30°-60°-90° triangle. A 30°-60°-90° triangle with a hypotenuse of 2 um

Step-by-step explanation:

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2 years ago

PQR is a right angled triangle calculate the size of angle marked x

romanna [79]

Answer:

$\displaystyle x \approx 37.4^\circ$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Trigonometry

[Right Triangles Only] SOHCAHTOA
[Right Triangles Only] cosθ = adjacent over hypotenuse

Step-by-step explanation:

Step 1: Define

Angle θ = x

Adjacent Leg = 5.8

Hypotenuse = 7.3

Step 2: Solve for x

Substitute in variables [Cosine]: $\displaystyle cosx^\circ = \frac{5.8}{7.3}$
[Fraction] Divide: $\displaystyle cosx^\circ = 0.794521$
[Equality Property] Trig inverse: $\displaystyle x^\circ = cos^{-1}(0.794521)$
Evaluate trig inverse: $\displaystyle x = 37.39^\circ$
Round: $\displaystyle x \approx 37.4^\circ$

8 0

2 years ago

Help ill give brainlest pls

Setler [38]

I the answer To You Problem Is C

6 0

1 year ago

Pleasee help I would appreciate very!​

Pleasee help I would appreciate very!