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3 years ago

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Find the solution of given expression

D%20" id="TexFormula1" title=" \sqrt{36 \times 36 \times 4} " alt=" \sqrt{36 \times 36 \times 4} " align="absmiddle" class="latex-formula">

2 answers:

Serggg [28]3 years ago

6 0

$\sqrt{36 \times 36 \times 4} = 72$

erica [24]3 years ago

4 0

Answer:

√(36×36×4)=√(36²×2²)=±(36×2)=±72

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The actual area is 454.1 ft.

You can use a ratio to find the actual diameter:
18cm/3cm = x/4ft.
x = 24 ft.

Then find the area using A=pi*r^2
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A=452.4 ft.

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For the right triangle shown, the lengths of two sides are given. Find the third side. Leave your answers in simplified, radical

PtichkaEL [24]

This is a simple Pythagorean theorem, which says that c2 = a2 + b2
So let us just apply it here:

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3 years ago

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27^x = 9^x − 4 Question 1 options: x = 8 x = 4 x = −4 x = −8

Mariulka [41]

Answer:

x = -8

Step-by-step explanation:

Given the equation:

$27^x=9^{x-4}$

Note that

$27=3^3\\ \\9=3^2,$

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Rewrite the equation as

$3^{3x}=3^{2(x-4)},$

then

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4 years ago

What is the value of x?

stiv31 [10]

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4 years ago

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The differential equation y′′=0y′′=0 has one of the following two parameter families as its general solution: yyyy=C1ex+C2e−x=C1

elena-14-01-66 [18.8K]

Answer:

$y(x)=6+9x$

Step-by-step explanation:

Given differential equation, $y''=0$

Characteristic equation is given by $m^2=0$

$\Rightarrow m=0,0$ .

Differential equation have repeated roots and solution of differential equation is $y(x)=C_1+C_2x$ .............................(1)

Initial conditions are $y(0)=6,y'(0)=9$

Plugging first condition in equation (1),

$6=C_1+C_2(0)$

$C_1=6$

Equation (1) becomes

$y(x)=6+C_2x$ ............................(2)

differentiate equation (2) with respect to 'x',

$y'(x)=C_2$

Plugging second condition,

$C_2=9$

Hence, $y(x)=6+9x$

3 0

3 years ago