Answer:
public class Main
{
public static void main(String[] args) {
System.out.println(min(3, -2, 7));
}
public static int min(int n1, int n2, int n3){
int smallest = Math.min(Math.min(n1, n2), n3);
return smallest;
}
}
Explanation:
*The code is in Java.
Create a method named min that takes three parameters, n1, n2, and n3
Inside the method:
Call the method Math.min() to find the smallest among n1 and n2. Then, pass the result of this method to Math.min() again with n3 to find the min among three of them and return it. Note that Math.min() returns the smallest number among two parameters.
In the main:
Call the method with parameters given in the example and print the result
<u>Answer:</u>
<em>int fNumber,scndNumber = -1, </em>
<em>dup = 0;
</em>
<em>do {
</em>
<em>cin >> fNumber;
</em>
<em>if ( scndNumber == -1) {
</em>
<em>scndNumber = fNumber;
</em>
<em>}
</em>
<em>else {
</em>
<em>if ( scndNumber == fNumber )
</em>
<em>duplicates++;
</em>
<em>else
</em>
<em>scndNumber = fNumber;
</em>
<em>}
</em>
<em>} while(fNumber > 0 ); </em>
<em>cout << dup;
</em>
<u>Explanation:</u>
Here three variables are declared to hold the first number which is used obtain all the inputs given by the user, second number to hold the value of <em>last encountered number and “dup” variable to count the number of duplicate values.</em>
<em>“Do-while”</em> loop help us to get the input check whether it is same as previous input if yes then it <em>adds to the duplicate</em> value otherwise the new previous value if stored.
Based on the definition which states it is an indicator of oxidation of an atom in a chemical compound. I believe the most viable answer is the charge of an atom's ion.
d- enjoy
b- national service !
