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vitfil [10]
3 years ago
10

Write an equation for the translation of "left 7 units Y=|x|

Mathematics
1 answer:
ss7ja [257]3 years ago
8 0

i need the answer to this lol

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In the above figure, the radius of curvature is 10 ft and the height of the segment is 2 ft. What's the length of the chord?
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The answer is 12. I am 1,000,000% positive that it is the correct answer

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I just need help at this point.
Greeley [361]

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Step-by-step explanation:you take the 740 and divide it by 40 to get the hourly wage then times that by the 32 and theirs your answer

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A paper is in the form of a rectangle ABCD in which AB= 18 cm and BC=14cm.A semicircular portion with BC as diameter is cut off.
svetoff [14.1K]

Answer:

remaining portion is area= area of rectangle- area of semicircle

= 18*14 - 3.14*7^2

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If it takes six men six days to dig six holes, how long will it take one man to dig half a hole?
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3 0
3 years ago
Find the​ (a) mean,​ (b) median,​ (c) mode, and​ (d) midrange for the data and then​ (e) answer the given question. Listed below
mafiozo [28]

Answer:

a) \bar X = 369.62

b) Median=175

c) Mode =450

With a frequency of 4

d) MidR= \frac{Max +Min}{2}= \frac{49+3000}{2}= 1524.5

<u>e)</u>s = 621.76

And we can find the limits without any outliers using two deviations from the mean and we got:

\bar X+2\sigma = 369.62 +2*621.76 = 1361

And for this case we have two values above the upper limit so then we can conclude that 1500 and 3000 are potential outliers for this case

Step-by-step explanation:

We have the following data set given:

49 70 70 70 75 75 85 95 100 125 150 150 175 184 225 225 275 350 400 450 450 450 450 1500 3000

Part a

The mean can be calculated with this formula:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

Replacing we got:

\bar X = 369.62

Part b

Since the sample size is n =25 we can calculate the median from the dataset ordered on increasing way. And for this case the median would be the value in the 13th position and we got:

Median=175

Part c

The mode is the most repeated value in the sample and for this case is:

Mode =450

With a frequency of 4

Part d

The midrange for this case is defined as:

MidR= \frac{Max +Min}{2}= \frac{49+3000}{2}= 1524.5

Part e

For this case we can calculate the deviation given by:

s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

And replacing we got:

s = 621.76

And we can find the limits without any outliers using two deviations from the mean and we got:

\bar X+2\sigma = 369.62 +2*621.76 = 1361

And for this case we have two values above the upper limit so then we can conclude that 1500 and 3000 are potential outliers for this case

5 0
3 years ago
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