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horsena [70]
2 years ago
9

Question 7

Mathematics
1 answer:
Ksenya-84 [330]2 years ago
3 0

Answer:

(4,2) and (2,-2)

Step-by-step explanation:

using m=y2-y1/x2-x1

m= -2-2/2-4=-4/-2

therefore,

m=2

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What is the slope of the line that passes through the points (12,-8) and (-9,-11)
Sauron [17]
Answer: 1/7


Explanation:

1. Use the formula, y2-y1/x2-x1
Plug in the points, (12, -8) and (-9, -11) into the formula.
Point (12, -8): 12 is the X1 and -8 is the y1.
Point (-9, -11): -9 is the X2 and -11 is the y2
So, -11--8/-9-12

2. -11--8/-9-12= -3/-21= 1/7

I hope this helps!!
3 0
2 years ago
Can I get help with this please?
sammy [17]
First equation:
5(x+1)=20 —— distribute the 5 to the x and 1
5x+5=20 ——- subtract 5 from 20
5x=15 ———— divide by 5 from both sides
X=3 ————— answer

Second equation:
5x+1=20——— subtract 1 from 20
5x=19 ———— divide by 5 from both sides
X=19/5———— answer in fraction form
X=3.8————- answer in decimal form
8 0
3 years ago
Given m varies directly with n and m = 6 when n = 5. what is the value of n when m = 12?
Rashid [163]

Answer:

n = 10

Step-by-step explanation:

given m varies directly as n then the equation relating them is

m = kn ← k is the constant of variation

to find k use the condition m = 6 when n = 5

6 = 5k ( divide both sides by 5 )

k = \frac{6}{5} = 1.2

m = 1.2n ← equation of variation

when m = 12 , then

12 = 1.2n ( divide both sides by 1.2 )

10 = n

7 0
2 years ago
Which ratios are proportional to 6/8 ? Choose all answers that are correct.
Step2247 [10]
3/4 is one of them and 12/16
6 0
3 years ago
Read 2 more answers
Find the area of the shaded region.
Citrus2011 [14]

Answer:

pi × 18cm^2

Or approximately,

56.52cm^2 (using 3.14 for pi)

or

56.5487cm^2 (using pi button on calculator)

Step-by-step explanation:

Area of a circle is pi times [radius squared].

All circles are 360°.

Problem can be solved by finding area of whole circle, and then using ratios.

Whole Circle: area = pi × (9cm)^2 = pi × 81cm^2

80° / 360° = Area[shaded] / (pi × 81cm^2)

pi × 18cm^2 = Area[shaded]

((If you read my answer before the edit, I am sorry. I made a calculator error.))

3 0
3 years ago
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