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Answer:
- Constraints: x + y ≤ 250; 250x +400y ≤ 70000; x ≥ 0; y ≥ 0
- Objective formula: p = 45x +50y
- 200 YuuMi and 50 ZBox should be stocked
- maximum profit is $11,500
Step-by-step explanation:
Let x and y represent the numbers of YuuMi and ZBox consoles, respectively. The inventory cost must be at most 70,000, so that constraint is ...
250x +400y ≤ 70000
The number sold will be at most 250 units, so that constraint is ...
x + y ≤ 250
Additionally, we require x ≥ 0 and y ≥ 0.
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A profit of 295-250 = 45 is made on each YuuMi, and a profit of 450-400 = 50 is made on each ZBox. So, if we want to maximize profit, our objective function is ...
profit = 45x +50y
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A graph is shown in the attachment. The vertex of the feasible region that maximizes profit is (x, y) = (200, 50).
200 YuuMi and 50 ZBox consoles should be stocked to maximize profit. The maximum monthly profit is $11,500.
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Special Considerations
Answer:
Step-by-step explanation:
The supplement to ∠1 = 180°-135° = 45° = ∠3, so m is parallel to j and l.
∠2 ≠ 45° and ∠2 ≠ 135°, so k is not parallel to j, l, or m.
Let the unknown number be x.
x × -7 = 7 (x + -40)
-7x = 7x - 280
-14x = -280
x = 280/14
x = 20
Hope this helps!
Answer:
Step-by-step explanation:
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