25 seats are in each section.
25 × 4 = 100
There are 100 seats in the auditorium.
Check the picture below.
let's recall that in a Kite, the diagonals meet at 90° angles, therefore, we know the height of each of those 4 triangles, is 2.5 and 6, now, since the pair of triangles above are 45-45-90 triangles, we can use the 45-45-90 rule, as you see there, so, if the height is 2.5, then the base is also 2.5.
so, we really have 2 pair of triangles whose base is 2.5 and height of 2.5, and another pair of triangles whose base is 2.5 and height is 6, let's add their areas.
![\bf \stackrel{\textit{area of 2 triangles above}}{2\left[\cfrac{1}{2}(2.5)(2.5) \right]}~~+~~\stackrel{\textit{area of 2 triangles below}}{2\left[ \cfrac{1}{2}(2.5)(6) \right]}\implies 6.25+15\implies 21.25](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7B%5Ctextit%7Barea%20of%202%20triangles%20above%7D%7D%7B2%5Cleft%5B%5Ccfrac%7B1%7D%7B2%7D%282.5%29%282.5%29%20%5Cright%5D%7D~~%2B~~%5Cstackrel%7B%5Ctextit%7Barea%20of%202%20triangles%20below%7D%7D%7B2%5Cleft%5B%20%5Ccfrac%7B1%7D%7B2%7D%282.5%29%286%29%20%5Cright%5D%7D%5Cimplies%206.25%2B15%5Cimplies%2021.25)
CD cost=17.50
Marked up=8%
So 8%of 17.50
8÷100×17.50=1.4
So add the old cd cost to the answer
=17.50+1.4=18.9 is the new cost
The beetle ate everything except the front cover of volume one and the back cover of volume four.
The thickness of the front cover of volume one and the back cover of volume four = 0.5 cm + 0.5 cm = 1 cm.
Total distance covered by the books = 4 x 8cm = 32 cm.
Therefore, total distance travelled by the beetle is 32 - 1 = 31 cm.