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Sveta_85 [38]
2 years ago
11

What is the missing numerator?

Mathematics
1 answer:
N76 [4]2 years ago
3 0

Answer:

  3

Step-by-step explanation:

As with any other addition fact problem, you can isolate the unknown term by subtracting the unwanted constant.

  5/7 +x/6 = 51/42

  x/6 = 51/42 -5/7 . . . . . subtract 5/7 from both sides

  x/6 = 51/42 -30/42 = 21/42 = 1/2 . . . . . complete the subtraction

  x = 6(1/2) = 3 . . . . . . . . multiply by 6

The missing numerator is 3.

_____

<em>Alternate solution</em>

Multiply the equation by 42:

  30 +7x = 51

  7x = 51 -30 = 21 . . . . . subtract 30

  x = 21/7 = 3 . . . . . . . . divide by the coefficient of x

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Step-by-step explanation:

A 10% increase is the same as multiplying a value by 1.1.

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en un maratòn participan corredores de todos los continentes 5/6 de los corredores son europeos se sabe que los americanos son l
Marysya12 [62]

Usando proporciones, se encuentra que 400 africanos han participado.

En total, hay x participantes.

\frac{5}{6} de los corredores son europeos, o sea:

E = \frac{5x}{6}

Los americanos son la dècime parte de los europeos, o sea:

Am = \frac{1}{10}E = \frac{5x}{60} = \frac{x}{12}

Los africanos son la quinta parte de los americanos, o sea:

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En la carrera han inscritos 24 000 participantes, o sea, x = 24000. Por eso, la cantidad de africanos es:

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Para obtener más información sobre las proporciones, puedes visitar a brainly.com/question/24615636

8 0
2 years ago
Help how do I solve this and how do I do it
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Answer:

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Step-by-step explanation:

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Which is the approximate solution to the system y = 0.5x + 3.5 and y = − 2/3 x + 1/3 shown on the graph? (–2.7, 2.1) (–2.1, 2.7)
AlekseyPX

Answer:

The approximate solution to the system is (-2.7, 2.1).

Step-by-step explanation:

To solve the system of equations \begin{bmatrix}y=0.5x+3.5\\ y=-\frac{2}{3}x+\frac{1}{3}\end{bmatrix} you must:

\mathrm{Rationalize\:equations}\\\\\begin{bmatrix}y=\left(\frac{1}{2}\right)x+\left(\frac{7}{2}\right)\\ y=-\frac{2}{3}x+\frac{1}{3}\end{bmatrix}

\mathrm{Subsititute\:}y=-\frac{2}{3}x+\frac{1}{3}\\\\\begin{bmatrix}-\frac{2}{3}x+\frac{1}{3}=\frac{1}{2}x+\frac{7}{2}\end{bmatrix}

\mathrm{Isolate}\:x\:\mathrm{for}\:-\frac{2}{3}x+\frac{1}{3}=\frac{1}{2}x+\frac{7}{2}\\\\-\frac{2}{3}x=\frac{19}{6}+\frac{1}{2}x\\\\-\frac{7}{6}x=\frac{19}{6}\\\\6\left(-\frac{7}{6}x\right)=\frac{19\cdot \:6}{6}\\\\-7x=19\\\\x=-\frac{19}{7}\approx-2.7

\mathrm{For\:}y=-\frac{2}{3}x+\frac{1}{3}\\\\\mathrm{Subsititute\:}x=-\frac{19}{7}\\\\y=-\frac{2}{3}\left(-\frac{19}{7}\right)+\frac{1}{3}\\\\y=\frac{15}{7}\approx 2.1

The approximate solutions to the system of equations are:

x=-2.7 ,\:y=2.1

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Step-by-step explanation:

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