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3 years ago

-30 plus a number equals 20. What is the number?

Mathematics

1 answer:

KatRina [158]3 years ago

8 0

Answer:

Step-by-step explanation:

-30+? =20

-30+50=20

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Pls help, and hurry. i will give anyone brainliest if you give the correct answer.

Anna11 [10]

Answer:

Two answers:

22 ≥ v

v ≤ 22

Step-by-step explanation:

It's the same as solving for a variable in an equality. Imagine it as 17 = v - 5 for a moment. Simplify by subtracting 5 from both sides and re-add the inequality sign. This can be easily done since we are not multiplying or dividing, just adding and subtracting.

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3 years ago

Junior Bodway, Incorporated, has provided the following budgeted data: Sales 10,000 units Selling price $ 50 per unit Variable e

Ksju [112]

Answer:

plz also help me its in my hw

Step-by-step explanation:

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3 years ago

Suppose a random variable, x, arises from a binomial experiment. If n = 25, and p = 0.85, find the variance. Round answer to 4 d

Tamiku [17]

Answer:

a) P(X=1) = 0.302526

b) P(X=5) = 0.010206

c) P(X=3) = 0.18522

d) P(X≤3) = 0.92953

e) P(X≥5) = 0.010935

f) P(X≤4) = 0.989065

If helpful, please mark as brainliest! =)

8 0

3 years ago

What is the solution to the equation 1^6 x = 2 ?

Dvinal [7]

1^6 is just 1 so 1x=2, you can just take away the one because it is a given that if there is an x there is a 1, so the answer is x=2

6 0

3 years ago

Enter the coefficients of the fifth Taylor polynomial T5(x) for the function f(x) = x5−3x4+2x2+5x−2 based at b=1. T5(x)= + (x−1)

DENIUS [597]

Compute the necessary values/derivatives of $f(x)$ at $x=1$ :

$f(1)=3$

$f'(1)=2$

$f''(1)=-12$

$f'''(1)=-12$

$f^{(4)}(1)=48$

$f^{(5)}(1)=120$

Taylor's theorem then says we can "approximate" (in quotes because the Taylor polynomial for a polynomial is another, exact polynomial) $f(x)$ at $x=1$ by

$T_5(x)=\dfrac3{0!}+\dfrac2{1!}(x-1)-\dfrac{12}{2!}(x-1)^2-\dfrac{12}{3!}(x-1)^3+\dfrac{48}{4!}(x-1)^4+\dfrac{120}{5!}(x-1)^5$

$T_5(x)=3+2(x-1)-6(x-1)^2-2(x-1)^3+2(x-1)^4+(x-1)^5$

###

Another way of doing this would be to solve for the coefficients $a,b,c,d,e,g$ in

$f(x)=a+b(x-1)+c(x-1)^2+d(x-1)^3+e(x-1)^4+g(x-1)^5$

by expanding the right hand side and matching up terms with the same power of $x$ .

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3 years ago