Answer:
16x^4+96x^3y+216x^2 y^2+216xy^3+81y^4
The number is 6 bc have of 12 is six
1. y - y₁ = m(x - x₁)
y - (-7) = 6(x - (-8))
y + 7 = 6(x + 8)
y + 7 = 6(x) + 6(8)
y + 7 = 6x + 48
<u> - 7 - 7</u>
y = 6x + 41
2. <u>y₂ - y₁</u> = <u>-8 - (-3)</u> = <u>-8</u><u> + 3</u> = <u>-5</u> = -1²/₃
x₂ - x₁ -1 - (-4) -1 + 4 3
3. 2x - 3y = 11
<u>3x + 3y = 9</u>
<u>5x</u> = <u>20</u>
5 5
x = 4
2x - 3y = 11
2(4) - 3y = 11
8 - 3y = 11
<u>- 8 - 8</u>
<u>-3y</u> = <u>3</u>
-3 -3
y = -1
(x, y) = (4, -1)
4. 2x - 5y = -7 ⇒ -6x + 15y = 21
5x - 3y = 11 ⇒ <u>-25x + 15y = -55</u>
<u>19x</u> = <u>76</u>
19 19
x = 4
2x - 5y = -7
2(4) - 5y = -7
8 - 5y = -7
<u>- 8 - 8</u>
<u>-5y</u> = <u>-15</u>
-5 -5
y = 3
(x, y) = (4, 3)
5. 4.9 × 10¹¹, 8.9 × 10¹⁸, 1.3 × 10⁸, 6.7 × 10⁸, 2.7 × 10⁸
<u>1.3 × 10³</u>, 2.7 × 10⁸, 6.7 × 10⁸, 4.9 × 10¹¹, <u>8.9 × 10¹⁸</u>
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-x^2+2x+3=x^2-2x+3 add x^2 to both sides
2x+3=2x^2-2x+3 subtract 2x from both sides
3=2x^2-4x+3 subtract 3 from both sides
2x^2-4x=0 factor
2x(x-2)=0
So x=0 and 2
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