Answer:
P(B/C) = 0.3333
Step-by-step explanation:
let's call B the event that a woman was wearing a belt and C the event that a woman was carrying a purse.
The probability P(B/C) that a woman was wearing a belt, given that the woman was also carrying a purse can be calculated as:
P(B/C) = P(B∩C)/P(C)
Where P(C) is the probability that a woman was carrying purse and P(B∩C) is the probability that the woman was both carrying purse and wearing belt.
So, P(C) is calculated as:
P(C) = 18 / 30 = 0.6
Because there were 30 women that walked by in an hour and of those women, 18 were carrying purses.
At the same way, P(B∩C) is equal to:
P(B∩C) = 6 / 30 = 0.2
Finally, P(B/C) is equal to:
P(B/C) = 0.2/0.6 = 0.3333
Answer: water tower because it's a tower
The are 40320 ways in which the 5 indistinguishable rooks be can be placed on an 8-by-8 chess- board so that no rook can attack another and neither the first row nor the first column is empty
<h3 /><h3>What involves the
rook polynomial? </h3>
The rook polynomial as a generalization of the rooks problem
Indeed, its result is that 8 non-attacking rooks can be arranged on an 8 × 8 chessboard in r8.
Hence, 8! = 40320 ways.
Therefore, there are 40320 ways in which the 5 indistinguishable rooks be can be placed on an 8-by-8 chess- board so that no rook can attack another and neither the first row nor the first column is empty.
Read more about rook polynomial
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12598 rounded to 10k = 10000