2 years ago

Help please i will give brainliest also have a great day

Mathematics

1 answer:

LUCKY_DIMON [66]2 years ago

4 0

Range 4
Mode 4
Median 4
Mean 5 ( rounded up from 4.7)

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If (1)=0, what are all the roots of the function f(x)=x3+3x2-x-3?use the remainder theorem

Anon25 [30]

If $f(1)=0$ , then by the remainder theorem $\dfrac{f(x)}{x-1}$ has a remainder of 0, which means $f(x)$ is divisible by $x-1$ . In fact,

$x^3+3x^2-x-3=x^2(x+3)-(x+3)=(x^2-1)(x+3)=(x-1)(x+1)(x+3)$

So we know 1 is a root, and the other two roots are -1 and -3.

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3 years ago

How do I solve this equation? 3|13-2t|=15

Nikolay [14]

$3 |13 - 2t | =15$ ⇒ $|13-2t| = 15\div3$ ⇒ $\boxed {|13-2t| = 5}$

$\hbox {We have two equations : 1. } |13-2t|=5$
$2.|13-2t|=-5$

$\hbox{The first: }$ ⇒ $13-2t=5$ ⇒ $2t=13-5$ ⇒ $2t=8$ ⇒ $\boxed {t=4}$

$\hbox { The second: } 13-2t=-5$ ⇒ $2t=13-(-5)=18$ ⇒ $\boxed {t=9}$

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3 years ago

Read 2 more answers

Solve for x <br> A) 12 <br> B) 11<br> C) 8 <br> D) 10

Furkat [3]

Answer:

B i would be good i solve 20 minutes

6 0

2 years ago

use distributive property to simplify the expression 3 (8x + 2y) I need help with my algebra homework someone please help.

inysia [295]

$6 \times (4 \times x + y)$

4 0

3 years ago

Use the given endpoint R and the midpoint M of segment RS to find the coordinates of the other endpoint S. (Hint: Use the midpoi

zimovet [89]

Using the given endpoint R (8,0)and the midpoint M (4,-5) , the other endpoint S is (0,-10)

Explanation :

Use the given endpoint R and the midpoint M of segment RS

R (8, 0 ) and M (4, -5 )

Let 'S' be (x2,y2)

Apply the midpoint formula

$(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} )\\$

Endpoint R is (x1,y1) that is (8,0)

Substitute the values and make it equal to M(4,-5)

$(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} )\\\\(\frac{8+x_2}{2},\frac{0+y_2}{2} )=(4,-5)\\\\\frac{8+x_2}{2}=4\\8+x_2=8\\x_2=8-8=0\\x_2=0\\\\\\\frac{0+y_2}{2} =-5\\y_2=-10$

So other endpoint S is (0,-10)

Learn more : brainly.com/question/16829448

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2 years ago