Y - x = 154
let z = xy = x(154 + x) = x^2 + 154x
we need to find the minimum value of z
z' = 2x + 154 which = zero for minm or maxm value
x = -77 and y = 154 -77 = 77
so the 2 numbers are -77 and 77
Answer:
(-2,1),(-1,2),(-3,5/3)
Step-by-step explanation:
The x-intercept of CD=18/5,0
Point lies on CD=32,-71
Answer: (x+8)(x+2) = x^2 + 10x + 16